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1 year ago

The options in the drop downs are: the margin of error will decrease / the margin of error will increase

Mathematics

1 answer:

shtirl [24]1 year ago

8 0

Answer:

mark me brainliest come to my account i got you 100 B i swear all i do is giveaway B but u gotta give it a thanks.

Step-by-step explanation:

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I do not get this question

postnew [5]

Hello!

When you put money into the bank you make a deposit

The answer is deposit

Hope this helps!

5 0

2 years ago

Read 2 more answers

I will give you BRAINLIEST

Sedbober [7]

Answer:

250

Step-by-step explanation:

If 5:7 = ?:350.

Since 350/7=50.

Multiply 5x50 =250.

Hope this helps! Have a great day!

3 0

1 year ago

15Points!!<br> Factor completely.<br><br><br> 12x² +28x

Zigmanuir [339]

Answer:

4x(3x+7)

Step-by-step explanation:

$12x^2+28x\\12xx+28x\\\\4\cdot \:3xx+4\cdot \:7x\\4x\left(3x+7\right)$

4 0

2 years ago

1.Arsenic-74 is used to locate brain tumors. It has a half-life of 17.5 days. 90 mg wereused in a procedure. Write an equation t

Sophie [7]

$1)\text{ }N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}$

2) 5.625 mg will be left

Explanation:

1) Half-life = 17.5 days

initial amount of Arsenic-74 = 90 mg

To get the equation, we will use the equation of half-life:

$\begin{gathered} N_t\text{ = N}_0(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}} \\ where\text{ N}_t\text{ = amount remaining} \\ N_0\text{ = initial amount} \\ t_{\frac{1}{2}\text{ }}\text{ = half-life} \end{gathered}$ $N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}$

2) we need to find the remaining amount of Arsenic-74 after 70 days

t = 70

$\begin{gathered} N_t=\text{ 90\lparen}\frac{1}{2})^{\frac{70}{17.5}} \\ N_t\text{ = 5.625 mg} \end{gathered}$

So after 70 days, 5.625 mg will be left

4 0

7 months ago

Given centerB with m∠ABD = 95 degrees

kirill [66]

Answer:

It would be the fourth one to me Yw

Step-by-step explanation:

8 0

2 years ago