Given J(1, 1), K(3, 1), L(3, -4), and M(1, -4) and that J'(-1, 5), K'(1, 5), L'(1, 0), and M'(-1, 0). What is the rule that tran
anastassius [24]
(x; y) -> (x - 2; y + 4)
J(1; 1) ⇒ J'(1 - 2; 1 + 4) = (-1; 5)
K(3; 1) ⇒ K'(3 - 2; 1 + 4) = (1; 5)
L(3;-4) ⇒ L'(3 - 2; -4 + 4) = (1; 0)
M(1;-4) ⇒ M'(1 - 2;-4 + 4) = (-1; 0)
Answer:
Bottom left
< means that it's dashed line
Answer:
Option G
Step-by-step explanation:
Option F
m∠1 + 121 = 180 [Sum of linear angles = 180°]
True.
Option G
121 + m∠2 + 33 = 180
False. Because 121° is not an interior angle of the given triangle.
Option H
33 + m∠1 = 92
True.
Measure of exterior angle of a triangle is equal to the sum of he measure of the non adjacent interior angles.
Option J
121 + 92 + m∠3 = 360°
True.
Sum of the exterior angles of triangle is 180°.
Answer:
None (x=∅)
Step-by-step explanation:
5(x - 3) + 6 = 5x - 10
5x-15+6 = 5x-10
-15+6+10=5x-5x
1 = 0
x = ∅