Answer: speed of jet A is 704 miles per hour
speed of jet B is 604 miles per hour
Step-by-step explanation:
Let the jets be jet A and jet B
Jet A and Jet B leave an air base at the same time and travel in opposite directions.
Let x = the speed of Jet A
Let y = the speed of jet B
One jet travels 100 miles an hour faster than the other. Let Jet A be the faster Jet. This means that
x = y + 100 - - - - - -1
If the two jets are 3924 miles apart after 3 hours, this means that both Jet A and Jet B travelled a total distance of 3924 miles after 3 hours.
Distance travelled = speed × time
Therefore,
Distance travelled by Jet A in 3 hours will be x × 3 = 3x miles.
Distance travelled by Jet B in 3 hours will be y × 3 = 3y miles.
Therefore, total distance is
3x + 3y = 3924 - - - - - - - -2
Substituting equation 1 into equation 2, it becomes
3(y+100) + 3y = 3924
3y + 300 + 3y = 3924
6y = 3924 - 300 = 3624
y = 3624/6 = 604 miles per hour
x = y + 100 = 604 + 100
x = 704 miles per hour
