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oksano4ka [1.4K]
3 years ago
9

A number is shown in word form. ''Seven hundred twenty-two thousand, five hundred" What is the number in standard form?​

Mathematics
1 answer:
VashaNatasha [74]3 years ago
8 0

Answer:

722,500

Step-by-step explanation:

we have:

Seven hundred twenty-two thousand,five hundred= 722,500

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The mean annual tuition and fees for a sample of 15 private colleges was with a standard deviation of . A dotplot shows that it
Fudgin [204]

Answer:

Step-by-step explanation:

The question is incomplete. The complete question is:

The mean annual tuition and fees for a sample of 15 private colleges was $35,500 with a standard deviation of $6500. A dotplot shows that it is reasonable to assume that the population is approximately normal. You wish to test whether the mean tuition and fees for private colleges is different from $32,500. State the null and alternate hypotheses. A) H0: 4 = 32,500, H:4=35,500 C) H: 4 = 35,500, H7:35,500 B) H: 4 = 32,500, H : 4 # 32,500 D) H0:41 # 32,500, H : 4 = 32,500

Solution

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0: µ = 32500

For the alternative hypothesis,

Ha: µ ≠ 32500

This is a two tailed test.

Since the number of samples is small and the population standard deviation is not given, the distribution is a student's t.

Since n = 15,

Degrees of freedom, df = n - 1 = 15 - 1 = 14

t = (x - µ)/(s/√n)

Where

x = sample mean = 35500

µ = population mean = 32500

s = samples standard deviation = 6500

t = (35500 - 32500)/(6500/√15) = 1.79

We would determine the p value using the t test calculator. It becomes

p = 0.095

Assuming alpha = 0.05

Since alpha, 0.05 < than the p value, 0.095, then we would fail to reject the null hypothesis.

7 0
3 years ago
A padlock has a four-digit code that includes digits from 0 to 9, inclusive. What is the probability that the code does not cons
Eduardwww [97]
Since there is no repetition allowed, there are 10 possibilities for the 1st digit, 9 for the 2nd, 8 for the 3rd, and 7 for the 4th. This gives a total of (10)(9)(8)(7) = 5040 four-digit codes.
For all odd digits to be used, there are 5 possibilities for the 1st digit (1,3,5,7,9), 4 for the 2nd, 3 for the 3rd, 2 for the 4th. This gives a total of (5)(4)(3)(2) = 120 codes that only use odd digits.
Therefore there are 5040 - 120 = 4920 codes that do not consist of all odd digits. The probability is 4920/5040 = 41/42.

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3 years ago
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Nuetrik [128]

Answer:

18

Step-by-step explanation:

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3 years ago
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Which of the following is an equivalent form of the compound inequality −33 &gt; −3x − 6 ≥ −6?
djyliett [7]

Answer:

-3x-6 < -33  and -3x-6 \geq -6

Step-by-step explanation:

we have

-33 > -3x-6 \geq -6

we know that

Compound inequality can be divided into two inequalities

so

-33 > -3x-6

rewrite

-3x-6 < -33

and

-3x-6 \geq -6

therefore

An equivalent form of the compound inequality is

-3x-6 < -33  and -3x-6 \geq -6

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The test score for a class pf 101 students are computed. What is the percentage of score equal to or grater than the third quart
irina [24]

Answer:

Step-by-step explanation:

The third quartile is at  75% of  total of number of students.

So percentage score great or equal to this is 25%.

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