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Hoochie [10]
3 years ago
12

(b) Scott added 8 fish to his pond each day for 64 days. What was the total change in the number

Mathematics
1 answer:
serious [3.7K]3 years ago
8 0

Answer:

512

Step-by-step explanation:

8 fish per day x 64 days

512 fish

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What expressions are equivalent to -56z + 28
makvit [3.9K]

Answer:

3b+b and 2(2b)

Step-by-step explanation:


4 0
3 years ago
The moon is a sphere with radius of 959 km. Determine an equation for the ellipse if the distance of the satellite from the surf
Sergeeva-Olga [200]

Answer:

\frac{x^2}{1316^2}+\frac{y^2}{1669^2}=1

Step-by-step explanation:

An ellipse is the locus of a point such that its distances from two fixed points, called foci, have a sum that is equal to a positive constant.

The equation of an ellipse with a center at the origin and the x axis as the minor axis is given by:

\frac{x^2}{b^2}+\frac{y^2}{a^2} =1 \\\\where\ a>b

Since the distance of the satellite from the surface of the moon varies from 357 km to 710 km, hence:

b = 357 km + 959 km = 1316 km

a = 710 km + 959 km = 1669 km

Therefore the equation of the ellipse is:

\frac{x^2}{1316^2}+\frac{y^2}{1669^2}=1

5 0
3 years ago
A phone manufacturer wants to compete in the touch screen phone market. He understands that the lead product has a battery life
alisha [4.7K]

Answer:

a)

The null hypothesis is H_0: \mu \leq 10

The alternative hypothesis is H_1: \mu > 10

b-1) The value of the test statistic is t = 1.86.

b-2) The p-value is of 0.0348.

Step-by-step explanation:

Question a:

Test if the battery life is more than twice of 5 hours:

Twice of 5 hours = 5*2 = 10 hours.

At the null hypothesis, we test if the battery life is of 10 hours or less, than is:

H_0: \mu \leq 10

At the alternative hypothesis, we test if the battery life is of more than 10 hours, that is:

H_1: \mu > 10

b-1. Calculate the value of the test statistic.

The test statistic is:

We have the standard deviation for the sample, so the t-distribution is used to solve this question

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

10 is tested at the null hypothesis:

This means that \mu = 10

In order to test the claim, a researcher samples 45 units of the new phone and finds that the sample battery life averages 10.5 hours with a sample standard deviation of 1.8 hours.

This means that n = 45, X = 10.5, s = 1.8

Then

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{10.5 - 10}{\frac{1.8}{\sqrt{45}}}

t = 1.86

The value of the test statistic is t = 1.86.

b-2. Find the p-value.

Testing if the mean is more than a value, so a right-tailed test.

Sample of 45, so 45 - 1 = 44 degrees of freedom.

Test statistic t = 1.86.

Using a t-distribution calculator, the p-value is of 0.0348.

5 0
3 years ago
Please answer the question below ​
Hatshy [7]

Answer:

g

Step-by-step explanation:

The maximum value occurs at gradient 0 (the stationary point).

In f this has a value (y) of 6.

In the equation example we have to differentiate:

dg(x)/dx = -x + 4

Gradient is 0 so 4 - x = 0 so x = 4

Plug g(4)=our maximum=-(1/2)4^2 + 4(4) + 3 = -8 + 16 + 3 = 11

11 > 6 so g has greater maximum.

7 0
3 years ago
Help me plsss its pretty easy lol
DaniilM [7]

Answer:

D, or the last one.

Step-by-step explanation:

Brainliest?

4 0
3 years ago
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