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JulijaS [17]
3 years ago
12

I need help with this question

Mathematics
2 answers:
Masja [62]3 years ago
5 0

Answer:

B (39)

Step-by-step explanation:

Using the Pythagorean theorem (a^2+b^2=c^2) and X=BC length

15^2+36^2=x

225+1296=x

√1521=x

x=39

Basile [38]3 years ago
4 0

Answer:

B.

Step-by-step explanation:

The Pythagorean Theorem

a^2+b^2=c^2

In this case it's c^2=a^2+b^2

c^2=15^2+36^2

c^2=225+1296

c^2=1521

c= the square root of 1521

c=39

So...

the length of line segment BC is 39

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How many different committees can be formed from 12 teachers Abs 43 students of the committee consists of 4 teachers and 3 stude
Marina86 [1]

Answer:

6108795

Step-by-step explanation:

To obtain the number of ways the committee can be selected :

4 teachers from the 12 teachers available and 3 students from the 43 students available

Using combinatorics :

12C4 * 43C3

recall :

nCr = n! ÷ (n - r)!r!

Using calculator :

12C4 = 495

43C3 = 12341

12C4 * 43C3

495 * 12341

= 6108795

3 0
2 years ago
Hihi , please help if able.
earnstyle [38]

Answer:

27

Step-by-step explanation:

3².2³/2² + 3².2²/2² = 27

7 0
3 years ago
Read 2 more answers
Determine the equation of a line that passrs through the point (4,-1) and also parallel to y=3x+4
nexus9112 [7]
First, plug in the given point into y=mx +b to find b (the y-intercept of the line). Use the same slope (m) in the equation since parallel lines have the same slope (3 in this case).

-1 = 3(4) +b
-1 = 12 + b Subtract 12 to both sides.
-13 = b

Now, put your m and b into y=mx+b.

The final answer/equation of your line is:

y=3x -13
5 0
3 years ago
A student solved the following problem and made an error: Triangles ABC and DEF. Angles A and F are congruent and measure 135 de
dmitriy555 [2]
We have that
triangle ABC coordinates
A (0,2)  B(2,4)  C(0,0)

triangle DEF coordinates 
D (2,0)  E ( 4,4)  F (4,2)

using a graph tool
see the attached figure

therefore

Line 1<span> Segment AC equals 2. Segment FE equals 2. Segment AC is congruent to segment FE 
</span>so
Segment AC equals 2-------> is correct
Segment FE equals 2-----> is correct
Segment AC is congruent to segment FE------> is correct

<span>Line 2 ∠A ≅ ∠F------> is correct
</span>
<span>Line 3 Length of segment AB. A (0, 2) B (2, 4) d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub 1 squared, d equals square root of quantity 0 minus 2 all squared plus quantity 2 minus 4 all squared, d equals square root of negative 2 squared plus negative 2 squared, d equals square root of 4 plus 4, d equals square root of 8 segment AB = 2.83
</span>
find the distance AB
d=√[(4-2)²+(2-0)²]--------> d=√[4+4]-----> d=√8-----> d=2.83
AB=2.83
so
Line 3 is correct

<span>Line 4 Length of segment DE. D (2, 0) E (4, 4) d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub squared, d equals square root of quantity 2 minus 4 all squared plus quantity 0 minus 4 all squared, d equals square root of negative 2 squared plus negative 4 squared, d equals square root of 4 plus 16, then d equals square root of 20 segment DE = 4.47
</span>
find the distance DE
d=√[(4-0)²+(4-2)²]--------> d=√[16+4]-----> d=√20-----> d=4.47
DE=4.47
so
Line 4------> is correct

<span>Line 5 segment AB is congruent with segment DE
AB is not congruent with DE
so
Line 5 is not correct

therefore

the answer is
</span><span>the student make the first mistake in line 5</span><span>

</span>

6 0
3 years ago
Maggie needs to spend at least six hours each week practicing the piano. She has already practiced three and one fourth hours th
vfiekz [6]

Answer:

three and one fourth + 2x ≥ 6

Step-by-step explanation:

Let

x -----> the minimum number of hours he needs to practice on each of the two days

we know that

needs to spend at least seven hours each week practicing the drums

so

3\frac{1}{4}+2x\geq 6\ hours

Convert mixed number to an improper fraction

3\frac{1}{4}\ hours=\frac{3*4+1}{4}=\frac{13}{4}\ hours

substitute

\frac{13}{4}+2x\geq 6\ hours

Subtract 13/4 both sides

2x\geq 6-\frac{13}{4}

2x\geq \frac{11}{4}

Divide by 2 both sides

x\geq \frac{11}{8}

therefore

The minimum number of hours he needs to practice on each of the two days is \frac{11}{8}\ hours

5 0
3 years ago
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