Answer:
The data we have is:
The acceleration is 3.2 m/s^2 for 14 seconds
Initial velocity = 5.1 m/s
initial position = 0m
Then:
A(t) = 3.2m/s^2
To have the velocity, we integrate over time, and the constant of integration will be equal to the initial velocity.
V(t) = (3.2m/s^2)*t + 5.1 m/s
To have the position equation, we integrate again over time, and now the constant of integration will be the initial position (that is zero)
P(t) = (1/2)*(3.2 m/s^2)*t^2 + 5.1m/s*t
Now, the final position refers to the position when the car stops accelerating, this is at t = 14s.
P(14s) = (1/2)*(3.2 m/s^2)*(14s)^2 + 5.1m/s*14s = 385m
So the final position is 385 meters ahead the initial position.
10: an isosceles base angles are both equal. A triangle has 3 angles. All three angles added equals 180 in every triangle. since one of the base angle is 72 degrees then the other base angle is 72 degrees. ( a triangle has two base angles). so 72+72= 144
180-144= 36
The vertex angle = 36 degrees.
11: angles ratio is 2:4:6. Remember that all angles equal 180. Add the ratio amounts, 2+4+6= 12. Then divide 180 by 12 (180/12 = 15).
the smallest angle ratio is 2, so multiply 15 by 2 ( 15 * 2= 30 )
the smallest angle is 30 degrees.
12: all three angles of a triangle adds up to 180. thus, 64 + 74 + x = 180
138 + x = 180
x= 180 - 138
x = 42
x is the third angle. so the third angle is 42 degrees.
Answer:
C = -10x+3
Step-by-step explanation:
So the simplified version of the main expression is -10x+3. after finding the main expression you just need to simplify the rest of them too.
A. = -10x+9
B. = 8x-9
C. = -10x+3
D. = -10x-3
Now that you simplified all the expressions, you can pick out the one that's the same as the target expression, which is C.
