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3 years ago

I need help with these

Mathematics

1 answer:

Sindrei [870]3 years ago

5 0

11. The answer to the question is d

12. (-3-3)/(-2+3)= -6/1=-6

y-3=-6(x+3)

y-3=-6x-18

y=-6x-15

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What are the steps to solve for: 1/5(x+5)=1/4(x-3)+1

andrew11 [14]

Step 1. Simplify $\frac{1}{5} (x+5)$ to $\frac{x+5}{5}$

$\frac{x+5}{5} = \frac{1}{4} (x-3)+1$

Step 2. Simplify $\frac{x+5}{5}$ to $1+ \frac{x}{5}$

$1+ \frac{x}{5} = \frac{1}{4} (x-3)+1$

Step 3. Simplify $\frac{1}{4} (x-3)$ to $\frac{x-3}{4}$

$1+ \frac{x}{5} = \frac{x-3}{4} +1$

Step 4. Cancel $1$ on both sides

$\frac{x}{5} = \frac{x-3}{4}$

Step 5. Multiply both sides by $20$ (the LCM of $5,4$ )

$4x=5(x-3)$

Step 6. Expand

$4x=5x-15$

Step 7. Subtract $5x$ from both sides

$4x-5x=-15$

Step 8. Simplify $4x-5x$ to $-x$

$-x=-15$

Step 9. Multiply both sides by $-1$

$x=15$

Done! :) Hope this helps! :)

3 0

3 years ago

A/ab-bsquare + b/ab-asquare?

lord [1]

Answer:

$\dfrac{(a+b)}{ab}$

Step-by-step explanation:

The given expression is :

$\dfrac{a}{ab-b^2}+\dfrac{b}{ab-a^2}$

It can be solved as follows :

$\dfrac{a}{ab-b^2}+\dfrac{b}{ab-a^2}=\dfrac{a}{b(a-b)}+\dfrac{b}{a(b-a)}\\\\=\dfrac{a}{b(a-b)}+\dfrac{b}{-a(-b+a)}\\\\=\dfrac{1}{a-b}(\dfrac{a}{b}-\dfrac{b}{a})\\\\=\dfrac{a^2-b^2}{ab(a-b)}\\\\=\dfrac{(a-b)(a+b)}{ab(a-b)}\\\\=\dfrac{(a+b)}{ab}$

So, the solution of the given expression is equal to $\dfrac{(a+b)}{ab}$ .

7 0

3 years ago

Shane bought lunch for $5.38 and a shirt for $15.95. He then used the rest of his money to buy a book. He spent a total of $38.1

barxatty [35]

You add $5.38 & $15.95, which equals $21.33. Then subtract $21.33 from $38.12. Your answer is $16.79. That's how much Shane spent on the book.

7 0

3 years ago

-6( - 3y - 6) - 10(6y - 8)

AnnyKZ [126]

Answer:

-2(21y-58)

Step-by-step explanation:

1.) Factor out -2 from the expression

2.)Distribute the three through the parenthesis

3.)distribute 5

4.)add the y’a together

5.)subtract -18-40

8 0

3 years ago

Which expression is equivalent to 32 ⋅ 3−5? fraction 1 over 3 to the power 3 fraction 1 over 3 to the power 7 fraction 1 over 3

mars1129 [50]

Given expression 3² × 3⁻⁵

We will apply the power rule $x^m*x^n=x^{m+n}$

3² × 3⁻⁵ = 3²⁺⁽⁻⁵⁾ = 3²⁻⁵ = 3⁻³

We will then apply the power rule $x^{-n} = \frac{1}{x^n}$

3⁻³ = $\frac{1}{3^3}$

Final answer: $\frac{1}{3^3}$

3 0

3 years ago

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