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tatuchka [14]
3 years ago
11

The equation of a line is y = 3x - 6

Mathematics
2 answers:
DiKsa [7]3 years ago
5 0

Answer:

-6

Step-by-step explanation:

dedylja [7]3 years ago
5 0

Answer:

The y- intercept is -6

y= mx+b is the formula  the y- intercept will always be "b"

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A toy airplane costs $4.84.. It costs 4 times as much as a toy car. What is the cost of the toy car? Show your work.
Elina [12.6K]
Cost of airplane toy = $4.84
let x be the cost of the toy car
cost of airplane toy is 4 times the cost of toy car; it means 
4x = $4.84
x = 4.84 / 4
x = 1.21
Thus, the cost of toy car is $1.21.
4 0
3 years ago
HELP ME PLEASE <br> PLEASE PLEASE PLEASE PLEASE PLEASE
Nimfa-mama [501]

Answer:

19y+5

Step-by-step explanation:

Combine like terms look for all the numbers that have y attached and combine them

7y +12y=19y

Look for terms where nothing is attached it's just the number combine them

6-1=5

Put all together again and you get:

19y+5

8 0
3 years ago
Please Fraction help &amp; explain
Anika [276]

Answer:

5/2

Step-by-step explanation:

Convert both fractions into improper fractions:

- To convert these fractions into an improper fraction you need to multiple the denominator with the mixed numeral/whole number. Then add that amount to the numerator. Do this for both fractions. This is what it should look like.

38/6 - 23/6.

The you subtract it

-       38/6 - 23/6 = 15/6

15/6 is your answer

If you want to simplify it the fraction it will be :

- 5/2

8 0
2 years ago
At a dairy farm the ratio of adult milking cows to young calves was 9:2. If there were 234 adult milking cows at the farm, how m
jok3333 [9.3K]

Answer:

52 young calves

Step-by-step explanation:

At a dairy farm the ratio of adult milking cows to young calves was 9:2. If there were 234 adult milking cows at the farm, how many young calves were there?

The ration is given as:

adult milking cows to young calves

= 9 : 2

= 234 : x

= 9/2 = 234/x

x = Number of young calves

Cross Multiply

9 × x = 2 × 234

= x = 2 × 234/9

x = 468/9

x = 52

Hence, the number of young calves on the farm is 52.

7 0
2 years ago
I don't know how to do this but I know you have to find the growth or decay
xenn [34]

Answer:

\boxed{y=5(1.05)^t\to\:5\% \:rate \:of \:growth}

\boxed{f(t)=50(.95)^t\to\:5\% \:rate \:of \:decay}

\boxed{g(t)=50(1.5)^t\to\:50\% \:rate \:of \:growth}

\boxed{y=5(.5)^t\to\:50\% \:rate \:of \:decay}

Step-by-step explanation:

We can rewrite the given functions in the form f(x)=a(100\%+r\%)^x to determine the rate of growth or f(x)=a(100\%-r\%)^x to determine the rate of decay

y=5(1.05)^t=5(100\%+5\%)^t\to\:5\% \:rate \:of \:growth

f(t)=50(.95)^t=50(100\%-5\%)^t\to\:5\% \:rate \:of \:decay

g(t)=50(1.5)^t=50(100\%+50\%)^t\to\:50\% \:rate \:of \:growth

y=5(.5)^t=5(100\%-50\%)^t\to\:50\% \:rate \:of \:decay

4 0
3 years ago
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