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Tresset [83]
3 years ago
14

Simplify and write the trigonometric expression in terms of sine and cosine: sinx + cotx cosx=1/f(x)

Mathematics
1 answer:
Lemur [1.5K]3 years ago
3 0

Answer:

Step-by-step explanation:

cot(x)=cos(x)/sin(x)

sin(x) + cos(x) * cos(x)/sin(x) = 1/f(x)

(sin^2 + cos^(x))/sin(x) = 1 / f(x)

1 / sin(x) = 1 / f(x)

Taking the reciprocal of both sides, we get

sin(x) = f(x)

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Distribute the problem <br> 2(3-8y)
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Answer:

<h3>6-16y</h3>

Step-by-step explanation:

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apply distributive law

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6 0
1 year ago
Lucy borrowed $425 from Colleen. Colleen charges Lucy 5.3% interest if Lucy pays Colleen back in 3 years how much does she pay C
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7 0
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Rex, Paulo, and Ben are standing on shore watching for dolphins. Paulo sees one surface directly in front of him about a hundred
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1. m\angle BAC=m\angle CAD,\ m\angle ACB=m\angle ADC=90^{\circ}, then m\angle ABC=m\angle ACD and triangles ADC and ACB are similar by AAA theorem.


2. The ratio of the corresponding sides of similar triangles is constant, so


\dfrac{AC}{AB}= \dfrac{AD}{AC}.


3. Knowing lengths you could state that \dfrac{b}{c}= \dfrac{e}{b}.


4. This ratio is equivalent to b^2=ce.


5. m\angle ABC=m\angle CBD,\ m\angle ACB=m\angle CDB=90^{\circ}, then m\angle BAC=m\angle BCD and triangles BDC and BCA are similar by AAA theorem.


6. The ratio of the corresponding sides of similar triangles is constant, so


\dfrac{BC}{BD}= \dfrac{AB}{BC}.


7. Knowing lengths you could state that \dfrac{a}{d}= \dfrac{c}{a}.


8. This ratio is equivalent to a^2=cd.


9. Now add results of parts 4 and 8:


b^2+a^2=ce+cd.


10. c is common factor, then:


b^2+a^2=c(e+d).


11. Since e+d=c you have a^2+b^2=c\cdot c=c^2.



7 0
2 years ago
Read 2 more answers
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