Solve the equation for the variable specified. df + 10h = 3 Solve for d. A. d 3= 10h f B. d. 3- 10h f C. d = 3 - 102 D. d = f(3
1 answer:
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Answer:
a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Step-by-step explanation:
I am going to solve this question treating these events as Venn probabilities.
I am going to say that:
Event A: Person has type A blood.
Event B: Person has Rh- factor.
43% of people have type O blood
This means that
15% of people have Rh- factor
This means that
52% of people have type O or Rh- factor.
This means that
a. Find the probability that a person has both type O blood and the Rh- factor.
This is
With what we have
0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b. Find the probability that a person does NOT have both type O blood and the Rh- factor.
1 - 0.06 = 0.94
0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.