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Darina [25.2K]
3 years ago
7

What would this be? I know its not 72.

Mathematics
1 answer:
nikdorinn [45]3 years ago
7 0

Answer:

324 units

Step-by-step explanation:

First find the measurements of the square.

24 ÷ 4 = 6

Each side of the square is 6 units.

Now scale by 3

6 × 3 = 18

Each side of the square is now 18 units

Find the area:

18 × 18 = 324

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What is the range of f(x)?<br> {xl-2 {x|-2 {yl-5 {yl-5 sy&lt;-1}
Bas_tet [7]

Answer:

-5≤y≤-1

Step-by-step explanation:

The range is the values that y takes

The smallest value of y is -5 and the largest value of y is -1

-5≤y≤-1

7 0
2 years ago
I NEED HELP :_( Which of the following points is in the solution set of y &gt; -x∧2 + 5? (0, 5) (2, 4) (1, 3)
marysya [2.9K]

Answer:

\huge\boxed{(2;\ 4)}

Step-by-step explanation:

We have

y>-x^2+5

Put the coordinates of the given points and check the inequality:

For (0; 5) → x = 0; y = 5

5>-0^2+5\\5>0+5\\5>5\qquad\bold{FALSE}

For (2; 4) → x = 2, y = 4

4>-2^2+5\\4>-4+5\\4>1\qquad\bold{TRUE}

For (1; 3) → x = 1, y = 3

3>1^2+5\\3>1+5\\3>6\qquad\bold{FALSE}

7 0
3 years ago
Student body elections are coming up and there are a lot of options. There are 3 candidates for president, 4 for secretary, and
kakasveta [241]

Answer:

1/120

Step-by-step explanation:

just took the test

8 0
2 years ago
Find the average rate of change of each function over the interval [0, 2]. Match each representation with its respective average
marishachu [46]
Average rate of change over interval [a,b]: r=[f(b)-f(a)]/(b-a)
In this case the interval is [0,2], then a=0, b=2
r=[f(2)-f(0)]/(2-0)
r=[f(2)-f(0)]/2

1) First function: h(x)
r=[h(2)-h(0)]/2
x=2→h(2)=(2)^2+2(2)-6
h(2)=4+4-6
h(2)=2
x=0→h(0)=(0)^2+2(0)-6
h(0)=0+0-6
h(0)=-6
r=[h(2)-h(0)]/2
r=[2-(-6)]/2
r=(2+6)/2
r=(8)/2
r=4

2) Second function: f(x)
A function, f, has an
x-intercept at (2,0)→x=2, f(2)=0
and a y-intercept at (0,-10)→x=0, f(0)=-10
r=[f(2)-f(0)]/2
r=[0-(-10)]/2
r=(0+10)/2
r=(10)/2
r=5

3) Third function: g(x)
r=[g(2)-g(0)]/2
From the graph:
g(2)=6
g(0)=2
r=(6-2)/2
r=(4)/2
r=2

4) Fourth function: j(x)
r=[j(2)-j(0)]/2
From the table:
x=2→j(2)=-8
x=0→j(0)=4
r=(-8-4)/2
r=(-12)/2
r=-6

Answer:
Pairs
1) h(x)     4
2) f(x)      5
3) g(x)     2
4) j(x)     -6
8 0
3 years ago
If each letter of the alphabet is worth two more than its preceding letter, where A is the first number and equals 1, B is the s
andrey2020 [161]

Answer:

<h2>The total value of all the letters in the alphabet is 676.</h2>

Step-by-step explanation:

The problem is about an arithmetic sequence where the difference is 2, the first term is 1 and we know that the alphabet has 26 letters.

To find the total sum of all values, we have to use the following formula

S_{n}=\frac{n}{2}(2a_{1}+(n-1)d )

Where n=26, a_{1}=1 and d=2. Replacing values, we have

S_{26}=\frac{26}{2}(2(1)+(26-1)2) =13(2+50)=13(52)=676

Therefore, the total value of all the letters in the alphabet is 676.

7 0
3 years ago
Read 2 more answers
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