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jolli1 [7]
3 years ago
12

Can someone show me how to solve this?

Mathematics
2 answers:
Makovka662 [10]3 years ago
8 0
C because u times it by 2
Vsevolod [243]3 years ago
4 0
V=πr^2h << that is how you set up the equation.

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Which of these problem types can not be solved using the Law of Sines?
andrezito [222]

I think the answer is B!

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Which transformation maps the pre-image, DEFG, to the image, D'E'F'G'?
netineya [11]
The answer is letter B. The image shows a relection because it is just the same as the original. Reflection is a transformation that gets the 2nd image just the same as the original. The transformation of DEFG is just the same as D'E'F'G'.
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Which plot has an outlier
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I believe Plot 1 is the girl's.The girls is an outlier




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3 years ago
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State the linear programming problem in mathematical terms, identifying the objective function and the constraints. A firm makes
Sedbober [7]

Answer:

Maximum profit at (3,0) is $27.

Step-by-step explanation:

Let  quantity of  products A=x

Quantity  of products B=y

Product A takes time on machine L=2 hours

Product A takes time on machine M=2 hours

Product B takes time on machineL= 4 hours

Product B takes time on machine M=3 hours

Machine L can used total time= 8hours

Machine M can used total time= 6hours

Profit on product A= $9

Profit on product B=$7

According to question

Objective function Z=9x+7y

Constraints:

2x+3y\leq 6

2x+4y\leq 8

Where x\geq 0, y\geq 0

I equation 2x+3y\leq 6

I equation in inequality change into equality we get

2x+3y=6

Put x=0 then we get

y=2

If we put y=0 then we get

x= 3

Therefore , we get two points A (0,2) and B (3,0) and plot the graph for equation I

Now put x=0 and y=0 in I equation in inequality

Then we get 0\leq 6

Hence, this equation is true then shaded regoin is  below the line .

Similarly , for II equation

First change inequality equation into equality equation

we get 2x+4y=8

Put x= 0 then we get

y=2

Put y=0 Then we get

x=4

Therefore, we get two points C(0,2)a nd D(4,0) and plot the graph for equation II

Point  A and C are same

Put x=0 and y=0 in the in inequality equation II then we get

0\leq 8

Hence, this equation is true .Therefore, the shaded region is below the line.

By graph we can see both line intersect at the points A(0,2)

The feasible region is AOBA and bounded.

To find the value of objective function on points

A (0,2), O(0,0) and B(3,0)

Put A(0,2)

Z= 9\times 0+7\times 2=14

At point O(0,0)

Z=0

At point B(3,0)

Z=9\times3+7\times0=27

Hence maximum value of z= 27 at point B(3,0)

Therefore, the maximum profit is $27.

6 0
3 years ago
Find the perimeter of shape #8
Wittaler [7]
The squiggly lines and the 2 straight lines through to sides of the pentagon mean that they are congruent (equal in length).

So, to find the perimeter of a regular polygon, you add all of its sides together.


So, the perimeter= 4x-2+x-2+x-2+x+2+x+2

To simplify it, add all of the x's together.

4x+x+x+x+x=8x

Perimeter=8x-2-2-2+2+2

-2-2=-4-2=-6+2=-4+2=-2

Perimeter=8x-2

Reach out to me if you have any questions. I'd be glad to help! :)
4 0
3 years ago
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