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geniusboy [140]
3 years ago
15

In a group of equal number of men and women 10% men and 45% women are suffering from Malaria.What is probability a peraon select

ed random is not suffering from Malaria?
Mathematics
1 answer:
Kaylis [27]3 years ago
4 0

Answer:

The probability a person selected random is not suffering from Malaria  is 0.725.

Step-by-step explanation:

Denote the events as follows:

X = a person is suffering from Malaria

M = a man

W = a woman

The information provided is:

P (M) = P (W) = 0.50

P (X|M) = 0.10

P (X|W) = 0.45

Compute the probability a person selected random is suffering from Malaria as follows:

P(X)=P(X|M)P(M)+P(X|W)P(W)

         =(0.10\times 0.50)+(0.45\times 0.50)\\\\=0.05+0.225\\\\=0.275

Then the probability a person selected random is not suffering from Malaria  is:

P (X') = 1 - P (X)

         = 1 - 0.275

         = 0.725

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Step-by-step explanation:

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A simple random sample of size n=10 is obtained from a population that is normally distributed with a mean of 40 and a standard
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Solution :

mean = μ40

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Step-by-step explanation:

We need to solve the system of equations

-9y + 4x-11 = 0- 3y + 10x + 31 = 0

Rearranging:

-9y + 4x = 11\,\,\,eq(1)\\- 3y + 10x=- 31 = 0\,\,\,eq(2)

Multiply eq(2) with 3 and subtract eq(2) from eq(1)

-9y + 4x = 11\\-9y+30x=-93\\+\,\,\,\,\,\,-\,\,\,\,\,\,\,\,\,\,\,\,+\\----------\\-26x=104\\x=\frac{104}{-26}\\x=-4

Putting value of x = -4 into eq(1)

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(-4,-3) is the solution of system of equations.

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