Question

In a group of equal number of men and women 10% men and 45% women are suffering from Malaria.What is probability a peraon selected random is not suffering from Malaria?

Answer 1

Answer:

The probability a person selected random is not suffering from Malaria  is 0.725.

Step-by-step explanation:

Denote the events as follows:

X = a person is suffering from Malaria

M = a man

W = a woman

The information provided is:

P (M) = P (W) = 0.50

P (X|M) = 0.10

P (X|W) = 0.45

Compute the probability a person selected random is suffering from Malaria as follows:

$P(X)=P(X|M)P(M)+P(X|W)P(W)$

         $=(0.10\times 0.50)+(0.45\times 0.50)\\\\=0.05+0.225\\\\=0.275$

Then the probability a person selected random is not suffering from Malaria  is:

P (X') = 1 - P (X)

         = 1 - 0.275

         = 0.725