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4 years ago

12

What is the value of y, if 3+12(y-4)=40?

1 answer:

creativ13 [48]4 years ago

4 0

3 + 12 (y-4) = 40 *Use distribution* 3 + 12y - 48 = 40 *combine like terms* -45 + 12y = 40 * what you do to one side of the equation you have to do to the other side -45 +12y = 40 +45 +45 ----------------------- 12y = 85 *now you divide to isolate variable* 85 ------- = 7 12 Y =7

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STALIN [3.7K]

Answer:

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Step-by-step explanation:

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3 years ago

Find sec 2Theta in exact value

forsale [732]

Answer:

$sec(2\theta)=-\frac{5}{4}$

Step-by-step explanation:

we know that

step 1

Find $cos(\theta)$

we know that

$tan^2(\theta)+1=sec^2(\theta)$

we have

$tan(\theta)=3$

substitute

$3^2+1=sec^2(\theta)$

$sec^2(\theta)=10$

$sec(\theta)=\pm\sqrt{10}$

Remember that

Angle theta lie in Quadrant I

so

$sec(\theta)$ is positive

$sec(\theta)=\sqrt{10}$

Remember that

$sec(\theta)=\frac{1}{cos(\theta)}$

therefore

$cos(\theta)=\frac{1}{\sqrt{10}}$

step 2

Find $sin(\theta)$

we know that

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

$sin(\theta)=tan(\theta)cos(\theta)$

we have

$cos(\theta)=\frac{1}{\sqrt{10}}$

$tan(\theta)=3$

substitute

$sin(\theta)=(3)(\frac{1}{\sqrt{10}})$

$sin(\theta)=\frac{3}{\sqrt{10}}$

step 3

Find $cos(2\theta)$

we know that

$cos(2\theta)=2cos^2(\theta)-1$

we have

$cos(\theta)=\frac{1}{\sqrt{10}}$

substitute

$cos(2\theta)=2(\frac{1}{\sqrt{10}})^2-1$

$cos(2\theta)=\frac{1}{5}-1$

$cos(2\theta)=-\frac{4}{5}$

Remember that

$sec(2\theta)=\frac{1}{cos(2\theta)}$

therefore

$sec(2\theta)=-\frac{5}{4}$

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3 years ago

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Alex_Xolod [135]

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4vir4ik [10]

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8 0

3 years ago

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ivanzaharov [21]

Answer:

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Step-by-step explanation:

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3 years ago

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