In order to get the common denominator when adding fractions or subtracting fractions, you have to make sure that the denominator of the two items are divisible by each other. In this case, 9 is not divisible by any of the given denominators which is 4 and 5. So in this case, the common denominator will have to be 20. 5 x 4 will equal to 20 and you will also multiply 3 x 5 to get the new numerator. After that, you will multiply 2 x 4 to get the new numerator of the other fraction. The new fractions will be 15/20 and 8/20. From there, you can add or subtract
Subtract 6 from 50:
50-6 = 44
Divide 44 by 2:
44/2 = 22
add 6:
22+6 = 28
There is 22 in the smaller class and 28 in the larger class.
The first Venn diagram would be the best because 18 students play baseball and one side has 13 13+5=18 and for basketball 12+5=17
Answerº the first Venn diagram.
Answer:
![\large\boxed{A=153\ cm^2}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7BA%3D153%5C%20cm%5E2%7D)
Step-by-step explanation:
<em>Look at the picture.</em>
We have
square with side length a = 9
trapezoid with base lengths b₁ = 9 and b₂ = 6 and the height length h = 6
right triangle with legs lengths l₁ = 3 + 6 = 9 and l₂ = 6
The formula of an area of a square
![A=a^2](https://tex.z-dn.net/?f=A%3Da%5E2)
Substitute:
![A_I=9^2=81\ cm^2](https://tex.z-dn.net/?f=A_I%3D9%5E2%3D81%5C%20cm%5E2)
The formula of an area of a trapezoid:
![A=\dfrac{b_1+b_2}{2}\cdot h](https://tex.z-dn.net/?f=A%3D%5Cdfrac%7Bb_1%2Bb_2%7D%7B2%7D%5Ccdot%20h)
Substitute:
![A_{II}=\dfrac{9+6}{2}\cdot6=\dfrac{15}{2\!\!\!\!\diagup_1}\cdot6\!\!\!\!\diagup^3=(15)(3)=45\ cm^2](https://tex.z-dn.net/?f=A_%7BII%7D%3D%5Cdfrac%7B9%2B6%7D%7B2%7D%5Ccdot6%3D%5Cdfrac%7B15%7D%7B2%5C%21%5C%21%5C%21%5C%21%5Cdiagup_1%7D%5Ccdot6%5C%21%5C%21%5C%21%5C%21%5Cdiagup%5E3%3D%2815%29%283%29%3D45%5C%20cm%5E2)
The formula of an area of a right triangle:
![A=\dfrac{l_1l_2}{2}](https://tex.z-dn.net/?f=A%3D%5Cdfrac%7Bl_1l_2%7D%7B2%7D)
Substitute:
![A_{III}=\dfrac{(9)(6)}{2}=\dfrac{54}{2}=27\ cm^2](https://tex.z-dn.net/?f=A_%7BIII%7D%3D%5Cdfrac%7B%289%29%286%29%7D%7B2%7D%3D%5Cdfrac%7B54%7D%7B2%7D%3D27%5C%20cm%5E2)
The area of the shape:
![A=A_I+A_{II}+A_{III}\\\\A=81+45+27=153\ cm^2](https://tex.z-dn.net/?f=A%3DA_I%2BA_%7BII%7D%2BA_%7BIII%7D%5C%5C%5C%5CA%3D81%2B45%2B27%3D153%5C%20cm%5E2)
Answer:
4.3, 4,5, 5.4, and 5.5
Step-by-step explanation: