Answer:
81.85%
Step-by-step explanation:
Given :
The average summer temperature in Anchorage is 69°F.
The daily temperature is normally distributed with a standard deviation of 7°F .
To Find:What percentage of the time would the temperature be between 55°F and 76°F?
Solution:
Mean = 
Standard deviation = 
Formula : 
Now At x = 55
At x = 76
Now to find P(55<z<76)
P(2<z<-1)=P(z<2)-P(z>-1)
Using z table :
P(2<z<-1)=P(z<2)-P(z>-1)=0.9772-0.1587=0.8185
Now percentage of the time would the temperature be between 55°F and 76°F = 
Hence If the daily temperature is normally distributed with a standard deviation of 7°F, 81.85% of the time would the temperature be between 55°F and 76°F.
Answer:
x>8
Step-by-step explanation:
4+3x>24
-4 -4
3x > 24
/3 /3
x > 8
Answer:
2.236
Step-by-step explanation:
you could estimate it to be between 2 and 3 (because 5 is between 4 and 9)
or you just put it into a calculator
Answer:
The number is 5
Step-by-step explanation:
Let x represent the number
Now let's break it down!
Sum of a number and 3 gives;
x + 3
This is then doubled to give;
2* (x + 3)
This is added to the product of 6 and the original number to give 46
Product of 6 and the original number = 6 * x
Now 2* (x + 3) is added to 6 * x to give 46
2* (x + 3) + 6*x = 46
2x + 6 + 6x = 46
8x + 6 = 46
Subtract 6 from both sides
8x + 6 - 6 = 46 - 6
8x = 40
x = 40/8
x = 5
Hence, the number is 5
I don't know. This seems tricky. But I do know that the probability would be 1 divided by the probability. So A and D is Incorrect. Theres never really a 50-50 chance with Locker doors so I'm gonna go with C.
I'm not guaranteed this is the answer. But I do Hope it helps. =)
