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3 years ago

Ng 20-21

Mathematics

2 answers:

Lisa [10]3 years ago

4 0

you would spend $30

Step-by-step explanation:

if 20 calculator cost 120 then you would divide 20 by 120 which would give you 6 dollars per calculator then you would multiply that by 5 which would give you a $30 for five calculators.

Minchanka [31]3 years ago

3 0

Answer:

where is the table?

I am just telling you how to get the cost of 5 calculators...

Step-by-step explanation:

Cost of 20 cal.=$120

Cost of 1 cal.=120/20

So,

cost of 5 calculators=

120/20*5

=$30

Hope it helps you

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Find x, find jl . any help is deeply appreciated :) !

Doss [256]

Answer:

6. x = 15

7. JL = 78

Step-by-step explanation:

6. 8x - 23 = ½(10x + 44) (midsegment theorem)

Multiply both sides by 2

2(8x - 23) = 10x + 44

16x - 46 = 10x + 44

Collect like terms

16x - 10x = 46 + 44

6x = 90

Divide both sides by 6

x = 90/6

x = 15

7. MN = 5x - 16

JL = 4x + 34

MN = ½(JL) (midsegment theorem)

5x - 16 = ½(4x + 34) (substitution)

2(5x - 16) = 4x + 34

10x - 32 = 4x + 34

Collect like terms

10x - 4x = 32 + 34

6x = 66

x = 66/6

x = 11

JL = 4x + 34

Plug in the value of x

JL = 4(11) + 34 = 44 + 34

JL = 78

4 0

2 years ago

-(-25m -3)

Soloha48 [4]

Answer:

25m + 3

Step-by-step explanation:

Break the bracket, you will get:

- -25m - (-3)

= + 25m + 3

= 25m + 3

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Viktor [21]

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$\left[0, \dfrac3n\right] \cup \left[\dfrac3n, \dfrac6n\right] \cup \left[\dfrac6n, \dfrac9n\right] \cup \cdots \cup \left[\dfrac{3(n-1)}n, 3\right]$

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$r_i = \dfrac{3i}n$

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Then the definite integral is given by the infinite Riemann sum

$\displaystyle \int_0^3 2x^2 \, dx = \lim_{n\to\infty} \sum_{i=1}^n 2{r_i}^2 \Delta x \\\\ ~~~~~~~~ = \lim_{n\to\infty} \frac6n \sum_{i=1}^n \left(\frac{3i}n\right)^2 \\\\ ~~~~~~~~ = \lim_{n\to\infty} \frac{54}{n^3} \sum_{i=1}^n i^2 \\\\ ~~~~~~~~ = \lim_{n\to\infty} \frac{54}{n^3}\cdot\frac{n(n+1)(2n+1)}6 = \boxed{18}$

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Delicious77 [7]

Answer:

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Step-by-step explanation:

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