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Luba_88 [7]
4 years ago
10

ANSWER ASAP!!!

Mathematics
1 answer:
Dafna11 [192]4 years ago
4 0
A.The greatest possible sum of a and b can be 47 if the two integers are -1 and 48
B.Yes it is possible. The two integers are-3 and 16.
C. The least possible difference is -49 if the two integers are 1 and -48
You might be interested in
A standard fair dice is rolled twice.
rusak2 [61]

Answer:

5/12

Step-by-step explanation:

The probability of rolling an odd number is 3/6, which is 1/2

The probability of rolling a factor of 12 is 5/6 (1,2,3,4,6)

1/2 x 5/6 = 5/12

5 0
3 years ago
Read 2 more answers
carl has 16 rubber balls to share with his 2 brother and 1 sister if carl and his brother and sister each get the same number​
Alexandra [31]
They each will get 4

Carl, his 2 brothers, and 1 sister. Total of 4 people. 16/4=4
3 0
3 years ago
Write -6 - 8i in polar form<br> Appreciate any help thank you so much!
Temka [501]
-6 = r cos α and  -8 = r sin α

r = sqrt( 6^2 + 8^2) = sqrt 100  = 10

α = arctan ( -8/-6) = arctan  (4/3) = 53.13 degrees

polar firm =  r ( cos α + i sin α)
                = 10(cos  53.18 +  i sin 53.18)

its been a long time but ui think thats correct
3 0
3 years ago
6. Let E, F, G be three events. Find expressions for the events that of E, F, G a. only E occurs; b. both E and G but not F occu
marta [7]

Answer:

a.) only E occurs :

E((FUG)')

b.) both E and G but not F

EG(F')

C.) Atleast one of the events :

(E U G U F)

d.) Atleast two of the events

(EG U EF U GF)

E.) all three occurs

(EGF)

F.) none of the events occur :

(E U G U F)'

G.) At most one of the events occur

(EG U EF U GF)'

H.) at most two of them occur

(E' U G' U F')

I.) exactly two of them occur;

(EG U EF U GF) * (EGF)'

j. at most three of them occur.

EFG U (EFG)'

Step-by-step explanation:

Events = {E, F, G}

a.) only E occurs :

E((FUG)') ; E and not F or G

b.) both E and G but not F

EG(F') ; both E and G and not F

C.) Atleast one of the events :

(E U G U F) ; Either E or F or G

d.) Atleast two of the events

(EG U EF U GF) ; Either EG or EF or GF occurs

E.) all three occurs

(EGF) ; All three events, E, G and F occurs

F.) none of the events occur :

(E U G U F)' ; Neither E, G nor F occurs

G.) At most one of the events occur

(EG U EF U GF)' ; complement of atleast two) at most one

H.) at most two of them occur

(E' U G' U F') ; Either E , F or G does not occur

I.) exactly two of them occur;

(EG U EF U GF) * (EGF)' ; Exactly two events occurs and all three events Do not occur

j. at most three of them occur.

EFG U (EFG)' ; All three events occur union all three events do not occur

6 0
3 years ago
Suppose that you were not given the sample mean and sample standard deviation and instead you were given a list of data for the
Troyanec [42]

Answer:

So, the sample mean is 31.3.

So, the sample standard deviation is 6.98.

Step-by-step explanation:

We have a list of data for the speeds (in miles per hour) of the 20 vehicles. So, N=20.

We calculate the sample mean :

\mu=\frac{19 +19 +22 +24 +25 +27 +28+ 37 +35 +30+ 37+ 36+ 39+ 40+ 43+ 30+ 31+ 36+ 33+ 35}{20}\\\\\mu=\frac{626}{20}\\\\\mu=31.3

So, the sample mean is 31.3.

We use the formula for a sample standard deviation:

\sigma=\sqrt{\frac{1}{N-1}\sum_{i=1}^{N}(x_i-\mu)^2}

Now, we calculate the sum

\sum_{i=1}^{20}(x_i-31.3)^2=(19-31.3)^2+(19-31.3)^2+(22-31.3)^2+(24-31.3)^2+(25-31.3)^2+(27-31.3)^2+(28-31.3)^2+(37-31.3)^2+(35-31.3)^2+(30-31.3)^2+(37-31.3)^2+(36-31.3)^2+(39-31.3)^2+(40-31.3)^2+(43-31.3)^2+(30-31.3)^2+(31-31.3)^2+(36-31.3)^2+(33-31.3)^2+(35-31.3)^2\\\\\sum_{i=1}^{20}(x_i-31.3})^2=926.2\\

Therefore, we get

\sigma=\sqrt{\frac{1}{N-1}\sum_{i=1}^{N}(x_i-\mu)^2}\\\\\sigma=\sqrt{\frac{1}{19}\cdot926.2}\\\\\sigma=6.98

So, the sample standard deviation is 6.98.

3 0
3 years ago
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