Answer:
C
Step-by-step explanation:
Calculate AC using Pythagoras' identity in ΔABC
AC² = 20² - 12² = 400 - 144 = 256, hence
AC = = 16
Now find AD² from ΔACD and ΔABD
ΔACD → AD² = 16² - (20 - x)² = 256 - 400 + 40x - x²
ΔABD → AD² = 12² - x² = 144 - x²
Equate both equations for AD², hence
256 - 400 + 40x - x² = 144 - x²
-144 + 40x - x² = 144 - x² ( add x² to both sides )
- 144 + 40x = 144 ( add 144 to both sides )
40x = 288 ( divide both sides by 40 )
x = 7.2 → C
Let's assume
the price of each train ticket is x
we are given
total number of family members =5
so, total cost of ticket = total number of family members*the price of each ticket
so, total cost of ticket =5*x
so, total cost of ticket =5x
now, we have
each family member buys a boxed lunch for $6.50
so, total cost of lunch box = total number of family members*price of each lunch box
so, total cost of lunch box = 5*6.50
total cost of trip = total cost of ticket+total cost of lunch box
we are given
total cost of trip is $248.50
now, we can plug values
and we get
now, we can solve for x
so,
the price of each train ticket is $43.2..........Answer