Question

This is probably easy

Answer 1

Answer:

5 hours

Step-by-step explanation:

Let's express each scenario as a function in a slope-intercept form, y = mx + b,

Where,

y = total amount of water

x = number of hours

m = rate of at which water is drained or filled per hour

b = initial quantity of water in the tank

✔️Equation for Tank A:

m = 2 gallons/hour = 2

b = 100 gallons = 100

Substitute m = 2 and b = 100 into y = mx + b:

y = 2x + 100

✔️Equation for Tank B:

m = 6 gallons/hour = -6 (this is negative 6 because water drains)

b = 140 gallons = 140

Substitute the values into y = mx + b

y = -6x + 140

✔️Set the two equation equal together to determine the number of hours (x) that must pass for the total amount of water (y) in tank A and tank B to be the same.

2x + 100 = -6x + 140

Collect like terms

2x + 6x = -100 + 140

8x = 40

Divide both sides by 8

x = 40/8

x = 5

Therefore, 5 hours must pass for the total amount of water in both tanks to be the same.