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3 years ago

8

How can you tell if an ordered pair (x,y) is a solution or a system of linear equations?

2 answers:

zubka84 [21]3 years ago

8 0

Answer:

you will know because it you do the system of whatever thingy and there are no two dots in the same row and the line is straight in either a negative or positive slope at a diagonal the equation is linear and its a function.

Step-by-step explanation:

The image is an example of a linear equation that is both a function and positive lenear

rusak2 [61]3 years ago

3 0

Answer:

To figure out if an ordered pair is a solution to an equation, you could perform a test. Identify the x-value in the ordered pair and plug it into the equation. When you simplify, if the y-value you get is the same as the y-value in the ordered pair, then that ordered pair is indeed a solution to the equation.

Step-by-step explanation:

You might be interested in

Is 6/7 greater than 4/6?

Oxana [17]

Yes, because 6/7 is the same as 36/42 and 4/6 is the same as 28/42. It is easy to see that 6/7 is greater than 4/6

7 0

3 years ago

Read 2 more answers

If r and s are positive integers, is \small \frac{r}{s} an integer? (1) Every factor of s is also a factor of r. (2) Every prime

Yuri [45]

Answer:

<em>If statement(1) holds true, it is correct that </em> $\small \frac{r}{s}$ <em> is an integer.</em>

<em>If statement(2) holds true, it is not necessarily correct that </em> $\small \frac{r}{s}$ <em> is an integer.</em>

<em></em>

Step-by-step explanation:

Given two positive integers $r$ and $s$ .

To check whether $\small \frac{r}{s}$ is an integer:

Condition (1):

Every factor of $s$ is also a factor of $r$ .

$r \geq s$

Let us consider an example:

$s = 5^2 \cdot 2\\r = 5^3 \cdot 2^2$

$\dfrac{r}{s} = \dfrac{5^3\cdot2^2}{5^2\cdot2} = 10$

which is an integer.

Actually, in this situation $s$ is a factor of $r$ .

Condition 2:

Every prime factor of <em>s</em> is also a prime factor of <em>r</em>.

(But the powers of prime factors need not be equal as we are not given the conditions related to powers of prime factors.)

Let

$r = 2^2\cdot 5\\s =2^4\cdot 5$

$\dfrac{r}{s} = \dfrac{2^3\cdot5}{2^4\cdot5} = \dfrac{1}{2}$

which is not an integer.

So, the answer is:

<em>If statement(1) holds true, it is correct that </em> $\small \frac{r}{s}$ <em> is an integer.</em>

<em>If statement(2) holds true, it is not necessarily correct that </em> $\small \frac{r}{s}$ <em> is an integer.</em>

<em></em>

8 0

3 years ago

the lenght of a rectangle is x+5 and it,s breath is x-5the areas of a rectangle is is x raise to the power of 2-x-15 is it true

sukhopar [10]

Answer:

False

Step-by-step explanation:

the area (A) of a rectangle is calculated as

A = length × breadth

= (x + 5)(x - 5) ← expand factors using FOIL

= x² - 5x + 5x - 25

= x² - 25 ≠ x² - x - 15

4 0

2 years ago

Help................

guapka [62]

Answer:

6.2 a QR

6.2 b 180

6.3 a By aas axiom

5 0

3 years ago

The diameter of a circle is 3.2 meters. Which is the circumference of the circle rounded to the nearest hundredth of a meter?

Paraphin [41]

Answer:

10.05 meters

Step-by-step explanation:

If the diameter is 3.2 meters, then the radius is 1.6 meters.

Use the circumference formula, C = 2 $\pi$ r, and solve for C

C = 2 $\pi$ r

C = 2 $\pi$ (1.6)

C = 3.2 $\pi$

C = 10.05

So, to the nearest hundredth of a meter, the circumference is 10.05 meters

4 0

3 years ago