PLEASE SOMEBODY HELP ASAP RIGHT ANSWERS ONLY!

A radio station ordered hats and coffee mugs to give away as prizes. A total of 1,000 of these items were ordered, and 3 times a

marshall27 [118]

Answer:

The options are not shown, so i will answer in a general way.

Let's define the variables:

h = number of hats

m = number of mugs.

We know that a total of 1000 items were ordered, then:

h + m = 1000

We also know that we have 3 times more mugs than hats, this can be written as:

m = 3*h

Now we have the system of equations:

h + m = 1000

m = 3*h

To solve these, we usually start by isolating one of the variables in one equation and then replace that in the other equation, but in this case, we already have m isolated in the second equation, then we can replace that in the first equation to get:

h + m = 1000

h + (3*h) = 1000

Now we can solve this equation for h, and find the number of hats ordered.

4*h = 1000

h = 1000/4 = 250

There were 250 hats ordered.

3 0

3 years ago

9. Carla has $200 in her bank account.

Firdavs [7]

(a) Linear Equation: $f(x) = 200 - 20x$

(b) x-intercept : (10,0)

(c) y-intercept : (0,200)

(d) Domain : {0,1,2,3,4,5,6,7,8,9,10}

Range : {0,1,2,...,200}

Step-by-step explanation:

Step 1: As we can see in graph, money in Carla is decreasing in multiples of 20 can be referred as 20x.

Every week $20 is getting deducted from the total amount of $200.

Step 2: (a) So we can quote it in equation as,

$f(x) = 200 - 20x$

where x represents number of weeks

Step 3: (b) x-intercept is where value of y becomes 0.

So, referring graph we can determine x intercept as x = 10. Point (10,0). which also means no money left in account.

Step 4: (c) y-intercept is where value of x becomes 0.

So, referring graph we can determine y intercept as y = 200. Point (0,200). which is starting value of money in account.

Step 5: (d) Domain : {0,1,2,3,4,5,6,7,8,9,10}

Range : {0,1,2,...,200}

4 0

3 years ago

How many zeros does the function y=x^2-8x-20 have

jenyasd209 [6]

The answer has 131;1 minutes

6 0

3 years ago

2. The National Safety Council routinely analyzes the benefit of seat belt use on driver safety. Their data showed that among 28

JulijaS [17]

Answer:

We conclude that there is difference in the proportion of deaths between the 2 groups.

Step-by-step explanation:

We are given that among 2823 drivers not wearing seat belts, 31 died as a result of injuries, and among 7765 drivers wearing seat belts 16 were killed.

Let $p_1$ = proportion of deaths when drivers were not wearing seat belts.

$p_2$ = proportion of deaths when drivers were wearing seat belts.

So, Null Hypothesis, $H_0$ : $p_1=p_2$ {means that there is no difference in the proportion of deaths between the 2 groups}

Alternate Hypothesis, $H_A$ : $p_1\neq p_2$ {means that there is difference in the proportion of deaths between the 2 groups}

The test statistics that would be used here Two-sample z test for proportions;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of deaths when drivers were not wearing seat belts = $\frac{31}{2823}$ = 0.011

$\hat p_2$ = sample proportion of deaths when drivers were wearing seat belts = $\frac{16}{7765}$ = 0.002

$n_1$ = sample of drivers not wearing seat belts = 2823

$n_2$ = sample of drivers wearing seat belts = 7765

So, the test statistics = $\frac{(0.011-0.002)-(0)}{\sqrt{\frac{0.011(1-0.011)}{2823}+\frac{0.002(1-0.002)}{7765} } }$

= 4.438

The value of z test statistics is 4.438.

Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistic doesn't lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that there is difference in the proportion of deaths between the 2 groups.

Also, Margin of error (E) = $1.96 \times \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} }$

= $1.96 \times \sqrt{\frac{0.011(1-0.011)}{2823}+\frac{0.002(1-0.002)}{7765} }$

= 0.00397

5 0

3 years ago

Ship A receives a distress signal from the southwest, and ship B receives a distress from the same vessel from the north. At wha

Fiesta28 [93]

I've attached an image showing the coordinates of Ship A and Ship B.

Answer:

distressed vessel is located at (1, 1.5)

Step-by-step explanation:

From the image attached, we can see that;

Coordinate of ship A is (3, 4)

Coordinate of ship B is (1, 1)

Now, we are told that Ship A receives a distress signal from the southwest, and ship B receives a distress from the same vessel from the north.

This means that the distressed ship is somewhere in between ship A & B.

To solve this, we will extend the arrow line from Ship A in that same SW direction and we will do the same for ship B in the same North direction. Their point of intersection is where the distressed ship is located.

Now, if we do that, we will see that they will intersect at the point; (1, 1.5)

Thus,distressed vessel is located at (1, 1.5)

5 0

4 years ago