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3 years ago

Subtract the following polynomials vertically. (8x + 5y + 4) - (32 - 9y - 5)

Mathematics

1 answer:

mash [69]3 years ago

6 0

8x+14y−23

Sorry if i'm wrong.. :)

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Help I don’t understand this ‍♀️

irina [24]

Hello there!
Point A is (-4,2)
Point B is (3,5)
Point C is (-2,-4)
Point D is (-3,1)
Point E is (0,-2)

6 0

3 years ago

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What is the value of F(5) in the function below?

Sever21 [200]

Answer:

Step-by-step explanation:

F(x) = 3^x

then

F(5) = 3^5 = 3×3×3×3×3 =243

6 0

3 years ago

The indefinite integral can be found in more than one way. First use the substitution method to find the indefinite integral. Th

Fantom [35]

Answer:

∫ $6x^5(x^6-2)\,dx$ = $\frac{1}{2}(x^6-2)^2+C$

Step-by-step explanation:

To find:

∫ $6x^5(x^6-2)\,dx$

Solution:

Method of substitution:

Let $x^6-2=t$

Differentiate both sides with respect to $t$

$6x^5\,dx=dt$

[use $(x^n)'=nx^{n-1}$ ]

So,

∫ $6x^5(x^6-2)\,dx$ = ∫ $t\,dt$ = $\frac{t^2}{2}+C_1$ where $C_1$ is a variable.

(Use ∫ $t^n\,dt=\frac{t^{n+1} }{n+1}$ )

Put $t=x^6-2$

∫ $6x^5(x^6-2)\,dx$ = $\frac{1}{2}(x^6-2)^2+C_1$

Use $(a-b)^2=a^2+b^2-2ab$

So,

∫ $6x^5(x^6-2)\,dx$ = $\frac{1}{2}(x^6-2)^2+C_1=\frac{1}{2}(x^{12}+4-4x^6)+C_1=\frac{x^{12} }{2}-2x^6+2+C_1=\frac{x^{12} }{2}-2x^6+C$

where $C=2+C_1$

Without using substitution:

∫ $6x^5(x^6-2)\,dx$ = ∫ $6x^{11}-12x^5\,dx$ = $\frac{6x^{12} }{12}-\frac{12x^6}{6}+C=\frac{x^{12} }{2}-2x^6+C$

So, same answer is obtained in both the cases.

7 0

2 years ago

Write an expression to<br> represent the perimeter of<br> the rectangle:<br> 3* +10<br> * +5

Schach [20]

Answer:

the perimeter is 18

Step-by-step explanation:

3 0

3 years ago

A 3-yard-long ribbon was used to trim for dresses. Each dress used the same amount of ribbon. How much ribbon was used for each

Tcecarenko [31]

Answer:

For x number of dresses, the answer is 3/x.

Step-by-step explanation:

Divide the length of the ribbon by the number of dresses.

If there were x dresses, the answer is 3/x.

6 0

3 years ago

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