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2 years ago

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Mathematics

1 answer:

myrzilka [38]2 years ago

4 0

Answer:

35 + 14 = 7 ( 5 + 2 )

Step-by-step explanation:

The distributive property to factor;

35 + 14

We do factors of both 7 * 5 + 2 * 7

Then take common 7 ( 5 + 2 ) 35 + 14 is 49

And 7 ( 7 ) = 49

Therefore 35 + 14 = 7 ( 5+2 )

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Determine whether the series is convergent or divergent. [infinity] n = 1 1 n√9 the series is a ---select--- p-series with p =

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The series is a convergent p-series with p = 3

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We would know that a series is a convergent p series when we have ∑ 1 np. Then you have to be able to tell if the series is a divergent p series or it is a convergent p series.

The way that you are able to tell this is if the terms of the series do not approach towards 0. Now when the value of p is greater than 1 then you would be able to tell that the series is a convergent series.

The value of $\sqrt{9}= 3$

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∑ $\frac{1}{n^p} \\$

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Can anyone explain to me how to do this question ? ty !!

julia-pushkina [17]

Step-by-step explanation:

use a little imagination.

the whole thing is a combination of churches and half- circles.

and you know the formula for the area of a circle ?

A = pi×r²

so, the only difficulty is to find the circles and then the radius of each involved circle.

when you look at the picture, the shaded area is almost identical to the lower half of the main circle.

2 bumps "look" over into the other side, but one equally sized bump is removed from this lower half.

so, as a first step we will calculate the area of the lower half of the main circle.

the diameter is 24 m, so the radius is half of that : 12m

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pi×12² = 144×pi m²

since we only need the (lower) half, we divide this by 2 :

144×pi / 2 = 72×pi m²

the bumps up and down are actually half-circles too. just of smaller circles.

since AB = BC = CD, we know each of these lines are 1/3 of the main diameter AD.

so, the diameter of the smaller circles is 24/3 = 8 m

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16×pi / 2 = 8×pi m²

so, for the full shaded area I need to take the large half-circle and add 2 small half-circles, and then subtract 1 small half-circle.

so, in total I only need to add 1 small half-circle.

Ashaded = 72×pi + 8×pi = 80×pi m²

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