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Answer:
The initial temperature of the object was 37.6 degrees Celsius
The initial temperature of the object was 37.6 (without units)
Step-by-step explanation:
we have
where
f(t) represent the temperature of the object in degree Celsius
t is the time in minutes
<em>Find the value of the constant C</em>
we have the ordered pair (4,35)
substitute in the equation and solve for C
Find the initial value of the object
we know that
The initial temperature is the value of f(t) when the value of t is equal to zero
so
For t=0
therefore
The initial temperature of the object was 37.6 degrees Celsius
The initial temperature of the object was 37.6 (without units)
If the discriminant is positive,that means that there are roots that are real and therefore, when y=0, the roots are there and for the quadratic to meet it has to go down (or up if in ax²+bx+c a is negative). If the discriminant is 0, that means that since the x value of the vertex is -b/2a and if you have
x=
and b^2-4ac=0, we're left with 0 and we are therefore left with -b/2a as the vertex and the vertex being the x intercept. If the discriminant is negative, that means that there is no y intercept and the vertex therefore has to be over y=0
x=