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tigry1 [53]
3 years ago
6

Which of the following lines is perpendicular to the equation given below?

Mathematics
2 answers:
konstantin123 [22]3 years ago
4 0

Answer:

C

Step-by-step explanation:

x+2y=8x...............

Travka [436]3 years ago
3 0

Answer:

  • B. x−2y=6

Step-by-step explanation:

Perpendicular lines have negative reciprocal slopes

<u>The given line is</u>

  • y = -2x + 8

<u>Perpendicular line to this must have a slope of </u>

  • - 1/(-2) = 1/2

<u>Option A</u>

  • 2x - y = 12
  • y = 2x - 12
  • Slope is 2
  • No

<u>Option B</u>

  • x - 2y = 6
  • 2y = x - 6
  • y = 1/2x - 3
  • Slope is 1/2
  • Yes

<u>Option C</u>

  • x + 2y = 8
  • 2y = - x + 8
  • y = -1/2x + 4
  • Slope is -1/2
  • No

<u>Option D</u>

  • 2x + y = 4
  • y = -2x + 4
  • Slope is -2
  • No
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Which function is the same as y = 3 cosine (2 (x startfraction pi over 2 endfraction)) minus 2? y = 3 sine (2 (x startfraction p
kirza4 [7]

The function which is same as the function y = 3cos(2(x +π/2)) -2 is: Option A: y= 3sin(2(x + π/4)) - 2

<h3>How to convert sine of an angle to some angle of cosine?</h3>

We can use the fact that:

\sin(\theta) = \cos(\pi/2 - \theta)\\\sin(\theta + \pi/2) = -\cos(\theta)\\\cos(\theta + \pi/2) = \sin(\theta)

to convert the sine to cosine.

<h3>Which trigonometric functions are positive in which quadrant?</h3>
  • In first quadrant (0 < θ < π/2), all six trigonometric functions are positive.
  • In second quadrant(π/2 < θ < π), only sin and cosec are positive.
  • In the third quadrant (π < θ < 3π/2), only tangent and cotangent are positive.
  • In fourth (3π/2 < θ < 2π = 0), only cos and sec are positive.

(this all positive negative refers to the fact that if you use given angle as input to these functions, then what sign will these functions will evaluate based on in which quadrant does the given angle lies.)

Here, the given function is:

y= 3\cos(2(x + \pi/2)) - 2

The options are:

  1. y= 3\sin(2(x + \pi/4)) - 2
  2. y= -3\sin(2(x + \pi/4)) - 2
  3. y= 3\cos(2(x + \pi/4)) - 2
  4. y= -3\cos(2(x + \pi/2)) - 2

Checking all the options one by one:

  • Option 1: y= 3\sin(2(x + \pi/4)) - 2

y= 3\sin(2(x + \pi/4)) - 2\\y= 3\sin (2x + \pi/2) -2\\y = -3\cos(2x) -2\\y = 3\cos(2x + \pi) -2\\y = 3\cos(2(x+ \pi/2)) -2

(the last second step was the use of the fact that cos flips its sign after pi radian increment in its input)
Thus, this option is same as the given function.

  • Option 2: y= -3\sin(2(x + \pi/4)) - 2

This option if would be true, then from option 1 and this option, we'd get:
-3\sin(2(x + \pi/4)) - 2= -3\sin(2(x + \pi/4)) - 2\\2(3\sin(2(x + \pi/4))) = 0\\\sin(2(x + \pi/4) = 0

which isn't true for all values of x.

Thus, this option is not same as the given function.

  • Option 3: y= 3\cos(2(x + \pi/4)) - 2

The given function is y= 3\cos(2(x + \pi/2)) - 2 = 3\cos(2x + \pi) -2 = -3\cos(2x) -2

This option's function simplifies as:

y= 3\cos(2(x + \pi/4)) - 2 = 3\cos(2x + \pi/2) -2 = -3\sin(2x) - 2

Thus, this option isn't true since \sin(2x) \neq \cos(2x) always (they are equal for some values of x but not for all).

  • Option 4: y= -3\cos(2(x + \pi/2)) - 2

The given function simplifies to:y= 3\cos(2(x + \pi/2)) - 2 = 3\cos(2x + \pi) -2 = -3\cos(2x) -2

The given option simplifies to:

y= -3\cos(2(x + \pi/2)) - 2 = -3\cos(2x + \pi ) -2\\y = 3\cos(2x) -2

Thus, this function is not same as the given function.

Thus, the function which is same as the function y = 3cos(2(x +π/2)) -2 is: Option A: y= 3sin(2(x + π/4)) - 2

Learn more about sine to cosine conversion here:

brainly.com/question/1421592

4 0
2 years ago
Read 2 more answers
Plssplsplsplspls answer fast bc its a map and I can't wait for way too long
AURORKA [14]

Answer:

Part A: 1

Part B: -4

Step-by-step explanation:

In a coordinate (x,y), the x-coordinate represents the input of a function and the y-coordinate represents the output.

Part A:

We're looking for the point the line passes through with an x-coordinate (input) of -3. This point is (-3,1) and therefore the output is 1 when the input is -3.

Part B:

We're looking for the point the line passes through with a y-coordinate (output) of 2. This point is (-4,2) and therefore an input of -4 yields an output of 2.

7 0
3 years ago
Read 2 more answers
The population of a town is growing exponentially and can be modeled by the
svp [43]

The population of the town in 1960 is 48.80 thousands

<h3>How to determine the population in 1950?</h3>

The equation of the model is given as:

f(t) = 42e^(0.015t)

1960 is 10 years after 1950.

This means that:

t = 10

Substitute t = 10 in f(t) = 42e^(0.015t)

f(10) = 42e^(0.015 * 10)

Evaluate

f(10) = 48.80

Hence, the population of the town in 1960 is 48.80 thousands

Read more about exponential functions at:

brainly.com/question/11464095

#SPJ1

7 0
2 years ago
What is this answer??
Gala2k [10]

Answer:

4/5

Step-by-step explanation:

0.80=80/100=40/50=4/5

5 0
3 years ago
Please help and Solve for x.
Serhud [2]

Answer:

tan70 = \frac{opp}{adj}  \\  \:  \:  =  \frac{15}{x }  \\  \\  x =  \frac{15 }{tan70 } \\   \\  =  \frac{15}{2.747}  \\  \\  = 5.46

since 5.46 is equal to 5.5...

I think the answer is the first one

7 0
3 years ago
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