This is the formula for a triangle base
b=2A
hb implement
If you have a question to ask, then what is it ?
I notice that IF AB and DE are parallel, then the two triangles tip to tip at C are similar. That may help you.
Answer:
EG = 19
Step-by-step explanation:
* Lets explain how to solve the problem
- If a line bisects another line that means the point of intersection
divides the second line into two equal parts
∵ EF bisects CD at G
∴ CG = GD
∵ CG = 5x - 1
∵ GD = 7x - 13
∴ 7x - 13 = 5x - 1
* Lets solve the equation
∵ 7x - 13 = 5x - 1
- Subtract 5x from both sides and add 13 to both sides
∴ 7x - 5x = 13 - 1
∴ 2x = 12
- Divide both sides by 2
∴ x = 6
- Point G divides EF into two parts EG and GF
∴ EF = EG + GF
∵ EF = 6x - 4
- Substitute the value of x to find EF
∵ x = 6
∴ EF = 6(6) - 4 = 36 - 4 = 32
∴ EF = 32
∵ GF = 13
- Substitute the values of EF and GF in the equation of EF
∴ 32 = EG + 13
- Subtract 13 from both sides
∴ 19 = EG
* EG = 19
Answer:
28
Step-by-step explanation:
f(n)=34, f(n-6)=34-6
=28
