Answer:In Heather's solution to the problem, she wrote and solved an equation.
Her work is:
Step 1: 1.08(x +9.01 +0.98 +5.01) = 21.87
Solving like terms
1.08(x+15}=21.87
dividing both side by 1.08
we get
x+15=21.87/1.08
x+15=20.25
subtracting both side by 13.9198
x=20.25-15
x=5.25
According to correction
;
<u>Option 1st</u>
<u>yes,it is correct</u>
Answer: C and D
Step-by-step explanation:I just did it my bad for the late response.
Answer:
1-i and -1+i
Step-by-step explanation:
We are to find the square roots of
. First, convert from Cartesian to polar form:



Next, use the formula
where
to find the square roots:
<u>When k=1</u>
<u />![\displaystyle \sqrt[2]{2}\biggr[cis\biggr(\frac{\frac{3\pi}{2}+2\pi(1)}{2}\biggr)\biggr]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csqrt%5B2%5D%7B2%7D%5Cbiggr%5Bcis%5Cbiggr%28%5Cfrac%7B%5Cfrac%7B3%5Cpi%7D%7B2%7D%2B2%5Cpi%281%29%7D%7B2%7D%5Cbiggr%29%5Cbiggr%5D)
![\displaystyle \sqrt{2}\biggr[cis\biggr(\frac{3\pi}{4}+\pi\biggr)\biggr]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csqrt%7B2%7D%5Cbiggr%5Bcis%5Cbiggr%28%5Cfrac%7B3%5Cpi%7D%7B4%7D%2B%5Cpi%5Cbiggr%29%5Cbiggr%5D)


<u>When k=0</u>
<u />![\displaystyle \sqrt[2]{2}\biggr[cis\biggr(\frac{\frac{3\pi}{2}+2\pi(0)}{2}\biggr)\biggr]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csqrt%5B2%5D%7B2%7D%5Cbiggr%5Bcis%5Cbiggr%28%5Cfrac%7B%5Cfrac%7B3%5Cpi%7D%7B2%7D%2B2%5Cpi%280%29%7D%7B2%7D%5Cbiggr%29%5Cbiggr%5D)


Thus, the square roots of -2i are 1-i and -1+i
Answer:
<h2>Diameter = 6 cm</h2>
Step-by-step explanation:
The formula of a volume of a sphere:

We have V = 36(3.14) cm³ = V = 36π cm³. Substitute:
<em>divide both sides by π</em>
<em>multiply both sides by 3</em>
<em>divide both sides by 4</em>
![R^3=27\to R=\sqrt[3]{27}\\\\R=3\ cm](https://tex.z-dn.net/?f=R%5E3%3D27%5Cto%20R%3D%5Csqrt%5B3%5D%7B27%7D%5C%5C%5C%5CR%3D3%5C%20cm)
The diameter D = 2R.
Therefore D = 2(3 cm) = 6cm
Answer:
x =4
Step-by-step explanation: