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Harlamova29_29 [7]
3 years ago
5

Consider the equation: x^2+10x+22=13 Need help asap!!!! this is due in a hour!

Mathematics
1 answer:
klio [65]3 years ago
7 0

Answer:

(x + 5)^2 = (5 - 3)^2

Step-by-step explanation:

Given the equation;

x^2 + 10x + 22 = 13

We have;

x^2 + 10x = 13 - 22

x^2 + 10x = -9

Adding half of 10 to both sides and completing the square as usual, we have;

(x + 5)^2 = 5^2 + (-9)

(x + 5)^2 = (5 - 3)^2

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<img src="https://tex.z-dn.net/?f=%28%20%5Csin%5E%7B2%7D%20%28%20%5Cfrac%7B%5Cpi%7D%7B%204%20%7D%20%20-%20%20%5Calpha%20%29%20%2
guapka [62]

Step-by-step explanation:

\sin^2 (\frac{\pi}{4} - \alpha) = \frac{1}{2}(1 - \sin 2\alpha)

Use the identity

\sin^2 \theta = \dfrac{1 - \cos 2\theta}{2}

on the left side.

\dfrac{1 - \cos [2(\frac{\pi}{4} - \alpha)]}{2} = \frac{1}{2}(1 - \sin 2\alpha)

\dfrac{1 - \cos (\frac{\pi}{2} - 2\alpha)}{2} = \frac{1}{2}(1 - \sin 2\alpha)

Now use the identity

\sin \theta = \cos(\frac{\pi}{2} - \theta)

on the left side.

\dfrac{1 - \sin 2\alpha}{2} = \frac{1}{2}(1 - \sin 2\alpha)

\frac{1}{2}(1 - \sin 2\alpha) = \frac{1}{2}(1 - \sin 2\alpha)

4 0
3 years ago
Which descriptions from the list below accurately describe the relationship between triangle QRS and triangle TUV check all that
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Answer:

Step-by-step explanation:

From the given figure, from ΔQRS and ΔTUV, we have

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∠R=∠U(83°(given))

∠S=∠V(41°(given))

Thus, by AAA similarity of triangles, ΔQRS is similar to ΔTUV.

Also, All the three angles made by both triangles are equal, and also they are similar thus they have same shape.

Thus, option C and D are correct.

6 0
4 years ago
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