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Lostsunrise [7]
3 years ago
8

Q1: Fill in the blanks:a) The number 3.23 can be expressed as fraction​

Mathematics
2 answers:
Len [333]3 years ago
7 0

Answer:

yes, as 3  23/100

Step-by-step explanation:

because

ozzi3 years ago
6 0

Answer:

I think it could be 3 23/100

Step-by-step explanation:

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Please help me solve this math problem
pochemuha

Answer:

 (b)

Step-by-step explanation:

A suitable calculator or spreadsheet can find the matrix product for you. Here, the answer choices differ in their upper left term, so we can determine the correct choice by finding the value of that term. It is the dot product of the first row of B and the first column of A.

  (5)(3) +(7)(3) +(3)(2) = 15 +21 +6 = 42

This matches choice B.

7 0
3 years ago
Choose the product. -5p 3(4p 2 + 3p - 1) -20p 5 - 15p 4 + 5p 3 -20p 6 - 15p 4 - 5p 3 -20p 5 + 3p - 1 20p 5 + 15p 4 - 5p 3
Likurg_2 [28]
<span>-5p^3(4p^2 + 3p - 1) = -20p^5 - 15p^4 + 5p^3

answer is

A. first one
  </span>-20p^5 - 15p^4 + 5p^3
5 0
3 years ago
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Using the distance formula, calculate how far Tre threw the ball. (4 points: 2 points for setup, 1 for calculation, 1 for the an
sergij07 [2.7K]

Answer:

D = 63.717

Step-by-step explanation:

The details that complete the question are:

(x_1,y_1) = (0,42.78)

and

(x_2,y_1)=(90,42.78)

Required

Determine how far the ball travelled

Distance is calculated using:

D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute values for x's and y's

D = \sqrt{(42.78 - 0)^2+(42.78-90)^2}

D = \sqrt{42.78^2+(-47.22)^2

D = \sqrt{1830.1284+2229.7284

D = \sqrt{4059.8568

D = 63.717

<em>Hence, the ball travelled a distance of 63.717 units</em>

6 0
3 years ago
Rhombus ADEF is inscribed into a triangle ABC so that they share angle A and the vertex E lies on the side BC . What is the leng
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Answer:

Length of side of rhombus is x=\frac{ab}{a+b}  

Step-by-step explanation:

Given Rhombus ADEF is inscribed into a triangle ABC so that they share angle A and the vertex E lies on the side BC. We have to find the length of side of rhombus.

It is also given that AB=a and AC=b

Let side of rhombus is x.

In ΔCEF and ΔCBA

∠CEF=∠CBA        (∵Corresponding angles)

∠CFE=∠CAB        (∵Corresponding angles)

By AA similarity rule, ΔCEF~ΔCBA

∴ their sides are in proportion

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⇒ \frac{x}{a}=\frac{b-x}{b}

⇒ xb=ab-ax

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