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3 years ago

Least to greatest 1.41 , 1.047, 1.444 (repeated), 1.4, 1.04

1 answer:

kramer3 years ago

5 0

We can put these decimals from least to greatest know which decimal points have greater values than the other. Tenth place, hundredth place, thousandth place, etc.

1.04, 1.047, 1.4, 1.41, 1.444.

Hope This Helped! Good Luck!

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Write the number seven hundred fifty -one with digits

Stells [14]

751......do u seriously need this?

6 0

2 years ago

draw a line representing the rise and a line representing the run of the line. State the slope of the line in simplest form

agasfer [191]

Answer:

m = -1

Step-by-step explanation:

The slope of a line is calculated as ;

Given : (-2,3) and (2,-1)

m = Δy/Δx

m= -1-3 /2--2

m = -4 /4 = -1

The slope is -1

4 0

3 years ago

What is 9.4 x 100 I need a quick answerr

abruzzese [7]

Answer: 940

Explanation: A quick way to think of this is moving the decimal in 9.4 to the right by two decimal places (since there are two zeroes in 100) Hope this helps! :)

8 0

3 years ago

Read 2 more answers

A car costs$cents when new. It was sold for four fifths of its cost price. How much money was lost on the car.

REY [17]

The question is incomplete as the cost price isn't given. However, taking the cost price as x :

Answer:

Kindly check explanation

Step-by-step explanation:

Given :

A car costs$cents when new. It was sold for four fifths of its cost price. How much money was lost on the car.

Let :

Cost price when new = x

Cost price when sold = 4/5 * cost price when new

Cost when sold = 4/5 of x = 4x/5

Amount of money lost on the car = (Cost price of car when new - Cost of car when sold)

Hence,

Amount of money lost on the car = (x - 4x/5)

x - 4x/5 = (5x - 4x) / 5 = x / 5

To obtain the exact price, kindly input the omitted cost when new for x.

7 0

2 years ago

You have just opened a new nightclub, Russ' Techno Pitstop, but are unsure of how high to set the cover charge (entrance fee). O

Neko [114]

Answer:

a)q(p)=-15p+ +300

b)R(p)=-15p²+300p

c)C(p)=-30p+1600

d.1)P(p)=-15p²+330p-1600

d.2)p=$11

Step-by-step explanation:

(a).Before getting started, we are going to consider the cartesian plane, where x-axis corresponds to the cover charge and y-axis corresponds to number of guests per night . There, we will locate the following coordinates according to the previous information:

(9,165) (10,150).

Remember that the slope-intercept form of the linear equation is y=mx+b where m is the slope and b is te intercept.

The slope can be calculated by the next formula:

$m=\frac{y2-y1}{x2-x1}$

In this case we will assign (9,165) as the first coordinate and (10,150) as the second one. The order does not matter. At the end we get the same value for m.

Therefore:

$m=\frac{150-165}{10-9} = -15$

Now, we have the slope and two poitns. According to this, and taking into account that point-slope form of the equation of a line is y-y1=m(x-x1), find a linear demand equation.

Any of two coordintates can be selected. In this case we will select the second one.

y-150=-15(x-10) equation 1

Solve equation 1 for y

y=-15x+150+150

y=-15x+300

Above we had defined x as cover charge (p) and y as number of guests (q). Thus, rewrite equation 1.

q(p)=-15p+ +300.

it equation shows the number of guests per night as a function of the cover charge,

(b). The nightly revenue can be calculated multplying the price of the cover charge by the number of guests. So, we just have to multiply the equation 1 by p.

p*q(p)=p*(-15p +300)

R(p)=-15p²+300p equation 2

(c) To get the cost function of the nightclub we just have to multiply the cost of the two non-alcoholic drinks by the number of the guests ( equation 1) and add to it nightly overheads.

C(p)=2*(-15p+300)+1000

C(p)= -30p+600+1000

C(p)=-30p+1600 equation 3

(d) In order to find the profit in terms of the cover charge we will subtract nightly costs ( equation 3) from nightly revenue (equation 2)

P(p)=R(p)-C(p)

P(p)=-15p²+300p - (-30p+1600)

P(p)=-15p²+300p+30p-1600

P(p)=-15p²+330p-1600

To determine that the entrance fee we should charge for a maximum profit we are going to use the first derivative test (y'(x)=0) in order to find an extremum point.

Compute the first derivative of P(p)

P'(p)=-30p+330=0

30p=330

p=330/30

p= $11

The entrance fee that we should charge for a maximum profit is p=$11 per guest.

5 0

3 years ago