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ivanzaharov [21]
3 years ago
6

Find the HCF of 12;28 and 32​

Mathematics
1 answer:
aleksley [76]3 years ago
5 0

Answer:

4

Step-by-step explanation:

  28 = 22 • 7  

   12 = 22 • 3  

   32 = 25

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Amy wants to sell at most 25 cookies and at least 10 sprites
Inga [223]

Answer:

x\leq 25\\y\geq 10\\.50x + y\geq 30

Step-by-step explanation:

It is given that,

Amy wants to sell at most 25 cookies ,

Let number of cookies be 'x' , then x should be less than or equal to 25

Which is represented by  x\leq 25 ,

Further,

Let number of sprites be 'y', then 'y' should be greater than or equal to  10

Which is represented by y\geq 10

Also,

Given,

she profits $.50 on every cookie

and $1.00 on every  sprite.

So total profit on selling cookies would be

= Profit on each cookie times the number of cookies

=.50\times x

=.5x

Similarly, total profit on selling sprites would be

=profit on each sprite times the number of sprites

=1.00\times y

=y

Now, combining these two should be greater than or equal to $30

representing this through an equation,

.50x+y\geq 30

Thus the sysytem of equations is given as:

x\leq 25\\y\geq 10\\.50x + y\geq 30

6 0
3 years ago
If x is 4 then y is
Eduardwww [97]

Answer:

2

Step-by-step explanation:

if x is 4 then y is 2 unlesss uknwo

6 0
3 years ago
Suppose the following number of defects has been found in successive samples of size 100: 6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6
Brut [27]

Answer:

Given the data in the question;

Samples of size 100: 6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6, 10, 9, 2, 8, 4, 8, 10, 10, 8, 7, 7, 7, 6, 14, 18, 13, 6.

a)

For a p chart ( control chart for fraction nonconforming), the center line and upper and lower control limits are;

UCL = p" + 3√[ (p"(1-P")) / n ]

CL = p"

LCL = p" - 3√[ (p"(1-P")) / n ]

here, p" is the average fraction defective

Now, with the 30 samples of size 100

p" =  [∑(6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6, 10, 9, 2, 8, 4, 8, 10, 10, 8, 7, 7, 7, 6, 14, 18, 13, 6.)] / [ 30 × 100 ]

p" = 234 / 3000

p" = 0.078

so the trial control limits for the fraction-defective control chart are;

UCL = p" + 3√[ (p"(1-P")) / n ]

UCL = 0.078 + 3√[ (0.078(1-0.078)) / 100 ]

UCL = 0.078 + ( 3 × 0.026817 )

UCL = 0.078 + 0.080451

UCL = 0.1585

LCL = p" - 3√[ (p"(1-P")) / n ]

LCL = 0.078 - 3√[ (0.078(1-0.078)) / 100 ]

LCL = 0.078 - ( 3 × 0.026817 )

LCL = 0.078 - 0.080451

LCL =  0 ( SET TO ZERO )

Diagram of the Chart uploaded below

b)

from the p chart for a) below, sample 28 violated the first western electric rule,

summary report from Minitab;

TEST 1. One point more than 3.00 standard deviations from the center line.

Test failed at points: 28

Hence, we conclude that the process is out of statistical control

Lets Assume that assignable causes can be found to eliminate out of control points.

Since 28 is out of control, we should eliminate this sample and recalculate the trial control limits for the P chart.

so

p" = 0.0745

UCL = p" + 3√[ (p"(1-P")) / n ]

UCL = 0.0745 + 3√[ (0.0745(1-0.0745)) / 100 ]

UCL = 0.0745 + ( 3 × 0.026258 )

UCL = 0.0745 + 0.078774

UCL = 0.1532

LCL  = p" - 3√[ (p"(1-P")) / n ]

LCL = 0.0745 - 3√[ (0.0745(1-0.0745)) / 100 ]

LCL = 0.0745 - ( 3 × 0.026258 )

LCL = 0.0745 - 0.078774

UCL = 0  ( SET TO ZERO )

The second p chart diagram is upload below;

NOTE; the red circle symbol on 28 denotes that the point is not used in computing the control limits

7 0
2 years ago
Volume of a cylinder with a 3 inch diameter is two times the volume of a cylinder with the same height in a 1/2 inch radius what
Alex73 [517]

Answer:

yes

Step-by-step explanation:

yes yes yes

5 0
3 years ago
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Answer:

መልሱ 78 ይሆናል ግን የጎደለው መላምት ፍጥነት ነው

Step-by-step explanation:

6 0
3 years ago
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