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In-s [12.5K]
3 years ago
9

8f=64. Solve the equation

Mathematics
2 answers:
Gekata [30.6K]3 years ago
5 0

Answer:

f = 8

Step-by-step explanation:

8f = 64

Divide

64 ÷ 8 = 8

<em>good luck, i hope this helps :)</em>

LekaFEV [45]3 years ago
4 0

Answer:

f = 8

Step-by-step explanation:

8f=64

divide both sides by 8

f=8

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PLEASE HELP GUYS i am struggling so much, two questions
ankoles [38]

Answer: the equation of the standard parabola

1) (y-6)^2 = 4 (x-1)

The equation of the standard parabola

2) (x+5)^2 = 16(y-2)

Step-by-step explanation:

<u>Explanation </u>

<u>Parabola:-</u>

The set of points in a plane whose distance from a fixed point and a constant ratio to their corresponding perpendicular distance from a fixed straight line is a conic.

Let S be a fixed point and l be a fixed straight line from any point P,the perpendicular PM is drawn to the line 'l'

  • The locus of P such that \frac{SP}{PM} = constant
  • The fixed point  'S' is called the Focus.
  • The fixed line'l 'is called the directrix of the conic
  • The constant ratio is known as the eccentricity, denoted by 'e'
  • If e=1 , the conic is called a parabola

1) <u> Step 1</u> :-

Given the focus   S = (2,6) and directrix is x=0

we know that \frac{SP}{PM}=1

now cross multiplication , we get

SP = PM

squaring on both sides,we get

SP^{2} = PM^2

step 2:-

now using distance formula is

  • \sqrt(((x_{2}-x_{1})^2+(y_{2} -y_{1} )^2)

Given S =(2,6) and P(x,y) be any point on parabola

SP^2 = (x-2)^2+(y-6)^2........(1)

Now using perpendicular distance formula

let P(x , y ) be any point on the parabola

  • \frac{ax_{1}+by_{1}+c   }{\sqrt{a^2+b^2} }

Given the directrix is x =0 and P(x,y) be any point on parabola

PM^2 = \frac{x^2}{\sqrt{1}^2 }......(2)

equating equation(1) and equation (2), on simplification

we get (x-2)^2+(y-6)^2 = x^2.....(3)

  • apply (a-b)^2 = a^2+  b^2+2 ab

now the equation (3) is

(y-6)^2 = 4 x-4

now the standard form of parabola is

(y-k)^2 = 4 a(x-h)

<u>Final answer</u>:-

(y-6)^2 = 4 (x-1)

2) <u> Explanation:-</u>

<u>step 1:</u>

Given vertex of a parabola is A(-5,2) and its focus is S(-5,6)

here the given points of 'x'co- ordinates are equal

  • Therefore the axis AS is parallel to y- axis

now the standard equation of parabola

(x-h)^2 = 4 a (y-k)

now you have to find' a' value

Given vertex of a parabola is A(-5,2) and its focus is S(-5,6)

The distance of AS = \sqrt{(-5-(-5)^2+(2-6)^2}

 on simplification we get a =4

<u>Final answe</u>r :-

the vertex (h,k) = (-5,2) and a=4

(x-h)^2 = 4 a (y-k)

The standard parabola is (x+5)^2 = 16 (y-2)

5 0
3 years ago
Aaro can run 4 miles in 30 minutes how long does it take him to run a mile
Sergio039 [100]

Answer: 7.5 minutes

Step-by-step explanation: divide 30 by 4.

5 0
3 years ago
Express 5940 as the product of prime factors.​
valentina_108 [34]

Step-by-step explanation:

5940 = 2×2×3×3×3×5×11

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5 0
2 years ago
Read 2 more answers
Please help ASAP! I’ll give brainliest:))
kompoz [17]

Answer with explanation:

After dilation about the origin(0,0) with the scale factor of 'k" , the image of the original point (x,y) becomes (kx,ky)

From the given graph, the coordinates of point C = (0,6)  [Since it lies on y-axis , the x-coordinate is zero]

After a dilation about the origin(0,0) with the scale factor of \dfrac{1}{2}, the new point will be (\dfrac{1}{2}\times0,\dfrac{1}{2}\times6)=(0,3)

Now plot this point on y-axis at y=3 as given in the attachment.

5 0
3 years ago
Five less than half a number is thirteen. What is the number?
Bad White [126]
-5+0.5x= 13

Add 5 to both sides
0.5x= 18

Multiply both sides by 2
x= 36

Final answer: x=36
6 0
3 years ago
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