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natta225 [31]
3 years ago
10

The relationship between time and distance remaining on a 3 mile walk for someone walking at a rate of 2miles per hour

Mathematics
1 answer:
Maksim231197 [3]3 years ago
6 0

Answer:

Remaining\ distance=3-2t\ \ \ \ \ \ \ \ \ (where\ t\ is\ time)

Step-by-step explanation:

Total\ distance=3\ mile\\\\speed=2\ miles/hour\\\\Time=t\\\\In\ t\ hours\ distance\ covered=velocity\times time=2\times t=2t\\\\Remaining\ distance=total\ distance-distance\ covered\\\\Remaining\ distance=3-2t

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If T(n) = 2n - 7 what is the 5th term
nadezda [96]
Plug in n = 5 to find the 5th term

T(5) = 2(5) - 7
T(5) = 10 - 7
T(5) = 3

The 5th term is 3.
3 0
3 years ago
Read 2 more answers
Between the years of 1947 and 1956, earthenware jars containing what are known as the Dead Sea Scrolls were found in caves along
lidiya [134]

Answer:

They are right, the time calculated using the exponential decay equation is 1948.6 years.

Step-by-step explanation:

The time can be calculated using the exponential decay equation:

N_{(t)} = N_{0}e^{-\lambda t}     (1)

<u>Where</u>:

N(t): is the quantity of C-14 at time t

N₀: is the initial quantity of C-14

λ: is the decay constant  

The decay constant is:

\lambda = \frac{ln(2)}{t_{1/2}}   (2)    

By entering equation (2) into (1) and solving for t, we have:

t = \frac{t_{1/2}*ln(N_{t}/N_{0})}{ln(2)} = \frac{5730*ln(0.79)}{ln(2)} = 1948.6 y

Therefore, the time of the scrolls estimated by the archeologists is right, since the time calculated using the exponential decay equation is 1948.6 years.      

I hope it helps you!

8 0
3 years ago
How many solutions are there to the following equation?
swat32

Answer:

D, infinitely many solutions

Step-by-step explanation:

1. multiply out

5(x-3) = 5x-15

2. combine like terms

5x-15-3x=8x-15-6x = 2x-15=2x-15

they are equal so there are infinite solutions.

8 0
3 years ago
If the plane intersects the cylinder horizontally, the cross section
mrs_skeptik [129]

Did you finish this question? I feel like you're missing something.

5 0
3 years ago
Consider that ΔXYZ is reflected across the y-axis and translated 2 units down.
DanielleElmas [232]

Answer:

X'Y' ≅ XY

∠Z ≅ ∠Z'

Step-by-step explanation:

we know that

A transformation that does not alter the size or shape of a figure is called a <u><em>Rigid Transformation</em></u>

Translations, rotations and reflections are rigid transformations

<u><em>Verify each statement</em></u>

case 1) X'Y' ≅ XY

The statement is true

Because

Reflecting and translating the triangle not change its shape or its size

The corresponding sides of the image and the pre-image are congruent

case 2) ∠Z ≅ ∠Z'

Because

Reflecting and translating the triangle not change its shape or its size

The corresponding angles of the image and the pre-image are congruent

case 3) ΔXYZ is not congruent to ΔX'Y'Z'

The statement is false

Because

ΔXYZ is congruent to ΔX'Y'Z'

case 4) Reflecting and translating the triangle change its shape and size

The statement is false

Because

Reflecting and translating the triangle not change its shape or its size

7 0
3 years ago
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