9514 1404 393
Answer:
- 3n+6 (n = smallest)
- 3n (n = middle)
Step-by-step explanation:
The usual method for doing this is to let n represent the smallest one. Then the three integers are ...
n, n+2, and n+4
and their sum is ...
(n) +(n+2) +(n+4) = 3n+6 . . . . sum of 3 consecutive odd integers (n = smallest)
_____
Personally, for consecutive number problems, I prefer to let the variable represent the average value. If n is the average value of 3 consecutive odd integers, is is the middle integer. Of course, the sum will be 3 times the average:
(n-2) +(n) +(n+2) = 3n . . . . sum of 3 consecutive odd integers (n = middle one)
Answer:
50⁰
Step-by-step explanation:
Since j and k are parallel lines cut by two transversals,
2+3+5=180⁰ <em>(</em><em>Allied</em><em> </em><em>angles</em><em>)</em>
We are given 2(60⁰) and 5(70⁰)
so,
60⁰+3+70⁰=180⁰
60+70=130
130⁰+3=180⁰
Bring the 130⁰ to the R.H.S
3=180⁰-130⁰
Therefore,
3=50⁰
C(1;2)
a = 1
b = 2
r = 4
(x-a)² + (y-b)² = r²
(x-1)² + (y-2)² = 4²
(x-1)² + (y-2)² = 16
That would simplify to 32x^5+400x^4+200x^3+5000x^2+6250x+3125
You would do that because you have to write it repeatedly as (2x+5)(2x+5) and so on.
find unit rate:
36 / 6 = 6
she can ride 6 miles in 1 hour
