A. Area of ABCD - Area of DGA = Area of DEFG
s^2 - 1/2bh = s^2
(5)^2 - 1/2(4)(3) = (3)^2
25 - 1/2(12) = 9
25 - 24 = 9
1 not equal to 9
B. Area of ABCD - Area of GHIA = Area of DGA
s^2 - s^2 = 1/2bh
(5)^2 - (4)^2 = 1/2(4)(3)
25 - 16 = 1/2(12)
9 not equal to 6
C. Area of ABCD + Area of DGA = Area of GHIA
s^2 + 1/2bh = s^2
(5)^2 + 1/2(4)(3) = (4)^2
25 + 1/2(12) = 16
25 + 6 = 16
31 not equal to 16
D. Area of DEFG + Area of GHIA = Area of ABCD
s^2 + s^2 = s^2
(3)^2 + (4)^2 = (5)^2
9 + 16 = 25
25 = 25
The answer is D.
Answer:
C. -2
Step-by-step explanation:
All parallel lines have the same slope
This question was answered but no solution was given.
We already solve for the B or area of the triangular base which was 5.25cm².
There are 2 triangular faces in the prism so 5.25cm² x 2 = 10.50cm²
There are 3 rectangular face in the prism, we need to get the area of each.
area of a rectangle = length x width
rectangle 1: 5 cm x 4 cm = 20 cm²
same dimension with rectangle 2. so, area is 20 cm² also
rectangle 3: 5 cm x 2.8 cm = 14 cm²
let us all add up the area of each surface.
2 triangle = 10.50 cm²
3 rectangles = 20 cm² + 20 cm² + 14 cm² = 54 cm²
10.50 cm² + 54 cm² = 64.50 cm²
Answer:
x=2
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
