Answer:
The loop will run 5 times.
Alternative 1:A small D-cache with a hit rate of 94% and a hit access time of 1 cycle (assume that no additional cycles on top of the baseline CPI are added to the execution on a cache hit in this case).Alternative 2: A larger D-cache with a hit rate of 98% and the hit access time of 2 cycles (assume that every memory instruction that hits into the cache adds one additional cycle on top of the baseline CPI). a)[10%] Estimate the CPI metric for both of these designs and determine which of these two designsprovides better performance. Explain your answers!CPI = # Cycles / # InsnLet X = # InsnCPI = # Cycles / XAlternative 1:# Cycles = 0.50*X*2 + 0.50*X(0.94*2 + 0.06*150)CPI= 0.50*X*2 + 0.50*X(0.94*2 + 0.06*150) / X1= X(0.50*2 + 0.50(0.94*2 + 0.06*150) ) / X= 0.50*2 + 0.50(0.94*2 + 0.06*150)= 6.44Alternative 2:# Cycles = 0.50*X*2 + 0.50*X(0.98*(2+1) + 0.02*150)CPI= 0.50*X*2 + 0.50*X(0.98*(2+1) + 0.02*150) / X2= X(0.50*2 + 0.50(0.98*(2+1) + 0.02*150)) / X= 0.50*2 + 0.50(0.98*(2+1) + 0.02*150)= 3.97Alternative 2 has a lower CPI, therefore Alternative 2 provides better performance.
Answer:
double x = 2.5;
double y = -1.5;
int m = 18;
int n = 4;
string s = "Storm";
string t = "Watch";
The output of the expression "x + n*y - (x+n)*y" is "6.25".
and the output of expression "m/n + m%n" is "6".
Explanation:
for the first expression,
x + n*y - (x+n)*y ,put value of every variables in it.
=2.5+4*(-1.5)-(2.5+4)*(-1.5)
=2.5-6.0-(6.5*(-1.5)
=-3.5+9.75
=6.25
for the second expression,
m/n + m%n, put value of every variables in it.
=18/4 +18%4
=4+2 ("/ will give quotient and % will give remainder")
=6
True, in order for the text color to be changed you have to select the entire text. If no text is selected one of two things will happen; either nothing will happen at all, or the next wors you type will be a different color.
