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sergiy2304 [10]
2 years ago
7

David worked in the library on Friday and Saturday he worked a total of 7 3/4 hours during these two days if he worked 4 1/4 Hou

rs on Friday then how many hours did he work on Saturday
Mathematics
1 answer:
aleksandr82 [10.1K]2 years ago
6 0

Answer:

3 1/2 hours.

Step-by-step explanation:

We subtract>

Number of hours worked on a Saturday

= 7 3/4 - 4 1/4

= (7 - 4) + (3/4 - 1/4)

= 3 + 1/2

= 3 1/2 hours.

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Andrew is 61 years. Erica is 31 years old. how many years ago was Andrew’s age 4 times Erica’s age
kozerog [31]

Answer:

21 Years Ago

Step-by-step explanation:

61 - 21 = 40

31 - 21 = 10

40/10 = 4

4 0
3 years ago
13 POINTS- please help me
allsm [11]

Answer:

See explanation

Step-by-step explanation:

16. Two parallel lines are cut by transversal. Angles with measures (6x+20)^{\circ} and (x+100)^{\circ} are alternate exterior angles. By alternate exterior angles, the measures of alternate exterior angles are the same:

6x+20=x+100\\ \\6x-x=100-20\\ \\5x=80\\ \\x=16

Then

(6x+20)^{\circ}=(6\cdot 16+20)^{\circ}=116^{\circ}\\ \\(x+100)^{\circ}=(16+100)^{\circ}=116^{\circ}

17. Two parallel lines are cut by transversal. Angles with measures (2x+12)^{\circ} and (3x-22)^{\circ} are alternate interior angles. By alternate interior angles, the measures of alternate interior angles are the same:

2x+12=3x-22\\ \\2x-3x=-22-12\\ \\-x=-34\\ \\x=34

Then

(2x+12)^{\circ}=(2\cdot 34+12)^{\circ}=80^{\circ}\\ \\(3x-22)^{\circ}=(3\cdot 34-22)^{\circ}=80^{\circ}

18. Two parallel lines are cut by transversal. Angles with measures (6x-7)^{\circ} and (5x+10)^{\circ} are alternate exterior angles. By alternate interior angles, the measures of alternate exterior angles are the same:

6x-7=5x+10\\ \\6x-5x=10+7\\ \\x=17

Then

(6x-7)^{\circ}=(6\cdot 17-7)^{\circ}=95^{\circ}\\ \\(5x+10)^{\circ}=(5\cdot 17+10)^{\circ}=95^{\circ}

19. The diagram shows two complementary angles with measures 2x^{\circ} and 56^{\circ}. The measures of complementary angles add up to 90^{\circ}, then

2x+56=90\\ \\2x=90-56\\ \\2x=34\\ \\x=17

Hence,

2x^{\circ}=2\cdot 17^{\circ}=34^{\circ}

Check:

34^{\circ}+56^{\circ}=90^{\circ}

20. Angles \angle 1 and \angle 2 are vertical angles. By vertical angles theorem, vertical angles are congruent, so

m\angle 1=m\angle 2\\ \\5x+7=3x+15\\ \\5x-3x=15-7\\ \\2x=8\\ \\x=4

Hence,

m\angle 1=(5x+7)^{\circ}=(5\cdot 4+7)^{\circ}=27^{\circ}\\ \\m\angle 2=(3x+15)^{\circ}=(3\cdot 4+15)^{\circ}=27^{\circ}

21. \angle 5 and \angle 8 are supplementary. The measures of supplementary angles add up to 180^{\circ}, so

m\angle 5+m\angle 8=180^{\circ}\\ \\3x-40+7x-120=180\\ \\10x-160=180\\ \\10x=180+160\\ \\10x=340\\ \\x=34

Therefore,

m\angle 5=(3x-40)^{\circ}=(3\cdot 34-40)^{\circ}=62^{\circ}\\ \\m\angle 8=(7x-120)^{\circ}=(7\cdot 34-120)^{\circ}=118^{\circ}\\ \\62^{\circ}+118^{\circ}=180^{\circ}

7 0
2 years ago
A local restaurant offers a deal if you purchase 3 medium pizzas you get 2 side dishes for free if you get a total of 8 side dis
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11 you count by 3 with the pizzas and 2 with the side dishes
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3 years ago
Simplify by combining like terms -17+2(6x-1)+5
earnstyle [38]

\huge\boxed{12x-14}

Start with the original expression.

-17+2(6x-1)+5

Use the Distributive Property — multiply 2 by both 6x and -1.

-17+12x-2+5

Combine the like terms — add up all the constants.

-14+12x

Reorder the terms.

\large\boxed{12x-14}

5 0
3 years ago
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Can someone please help me with question 4
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Yes what is the four question
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