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EastWind [94]
3 years ago
9

Factor completely 9x^2-25

Mathematics
1 answer:
attashe74 [19]3 years ago
4 0

Answer:

9x^{2}  - 25 = (3x -5)(3x+5)

Step-by-step explanation:

Here, the given expression  is 9x^{2}  - 25

Now, we know that 9  = 3^{2}  ,  25 = 5^{2}

So, the given expression is transformed in to

9x^{2}  - 25  = (3x)^{2}   - 5^{2}

Also, by <u>ALGEBRAIC IDENTITY</u>

a^{2} - b^{2} = (a-b)(a+b)

Similarly here taking :  a = 3x and b =5

(3x)^{2}   - 5^{2} = (3x -5)(3x+5)

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On a board measuring 1x100, each square is numbered from
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Answer:

97

Step-by-step explanation:

Given the following conditions :

board measuring 1x100, each square is numbered from 1 to 100

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What is the highest numbered square that is painted blue?

The sequence of painting is repeated after :

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Since the number of squares = 100

Maximum complete repetition possible :

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If sin=3 by 5 and cos =4 by 5 find tan​
Afina-wow [57]

Answer:

<h3>3/4</h3>

Step-by-step explanation:

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3 years ago
1. The sum of a two-digits number is 13. The tens digit is 8 less than twice the units digit. What is the number?
alexgriva [62]

Answer:

<u>The number is 67</u>

Step-by-step explanation:

<u>Equations</u>

Let's consider the number 83. The tens digit is 8 and the unit digit is 3. Note the tens digit's addition to the number is 80, and the unit's addition is 3. This means the tens digit adds 10 times its value, that is, 83 = 8*10 + 3.

Now, let's consider the number ab, where a is the tens digit, and b is the unit digit. It follows that

Number=10*a+b

The question gives us two conditions:

1) The sum of a two-digits number is 13.

2) The tens digit is 8 less than twice the units digit.

The first condition can be expressed as:

a + b = 13                     [1]

And the second condition can be written as:

a = 2b-8                      [2]

Replacing [2] into [1], we have:

2b-8 + b = 13

Operating:

3b = 13 + 8

3b = 21

Solving for b:

b = 21 / 3 = 7

Substituting into [2]:

a = 2*(7) - 8 = 6

Thus, the number is 67

3 0
4 years ago
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