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Free_Kalibri [48]
3 years ago
13

I NEED HELP PLS IM BEING TIMED PLSSSSSSSSSSSSSSSSSSSSSS

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
5 0

Answer: 7/9

Step-by-step explanation:

The square root of 49 is 7, and the square root of 81 is 9.

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The vertex form of a function is g(x) = (x – 3)2 + 9. How does the graph of g(x) compare to the graph of the function f(x) = x2?
Alekssandra [29.7K]

we have

g(x)=(x-3)^{2}+9

This is the equation of a vertical parabola with vertex at point (3,9)

The parabola open upward------> the vertex is a minimum

f(x)=x^{2}

This is the equation of a vertical parabola with vertex at point (0,0)

The parabola open upward------> the vertex is a minimum

so

the rule of the translation is

f(x)------> g(x)

(x,y)-----> (x+3,y+9)

that means

the translation is 3 units to the right and 9 units up

the graph of the function g(x) is the translated graphic of the function f(x) 3 units to the right and 9 units up

therefore

<u>the answer is</u>

g(x) is shifted 3 units right and  9  units up

8 0
3 years ago
Read 2 more answers
Find the following sums <br> 4 + 7 + 10 + 13 + ... +40 + 43
Fantom [35]

Answer:

117

Step-by-step explanation:

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4 0
3 years ago
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A rat is trapped in a maze. Initially he has to choose one of two directions. If he goes to the right, then he will wander aroun
Brut [27]

Answer:

The expected number of minutes the rat will be trapped in the maze is 21 minutes.

Step-by-step explanation:

The rat has two directions to leave the maze.

The probability of selecting any of the two directions is, \frac{1}{2}.

If the rat selects the right direction, the rat will return to the starting point after 3 minutes.

If the rat selects the left direction then the rat will leave the maze with probability \frac{1}{3} after 2 minutes. And with probability \frac{2}{3} the rat will return to the starting point after 5 minutes of wandering.

Let <em>X</em> = number of minutes the rat will be trapped in the maze.

Compute the expected value of <em>X</em> as follows:

E(X)=[(3+E(X)\times\frac{1}{2} ]+[2\times\frac{1}{6} ]+[(5+E(X)\times\frac{2}{6} ]\\E(X)=\frac{3}{2} +\frac{E(X)}{2}+\frac{1}{3}+\frac{5}{3} +\frac{E(X)}{3} \\E(X)-\frac{E(X)}{2}-\frac{E(X)}{3}=\frac{3}{2} +\frac{1}{3}+\frac{5}{3} \\\frac{6E(X)-3E(X)-2E(X)}{6}=\frac{9+2+10}{6}\\\frac{E(X)}{6}=\frac{21}{6}\\E(X)=21

Thus, the expected number of minutes the rat will be trapped in the maze is 21 minutes.

3 0
4 years ago
What is the factored form of the following expression? <br><br> W^2 + 18w + 77
Lorico [155]

Answer:

(w + 11)(w + 7)

Step-by-step explanation:

Consider the factors of the constant term ( + 77) which sum to give the coefficient of the w- term ( + 18)

The factors are + 11 and + 7, since

11 × 7 = 77 and + 11 + 7 = + 18

w² + 18w + 77 = (w + 11)(w + 7)

3 0
4 years ago
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11a – 4(a + 2) &lt; 8a + 10
kirill115 [55]

Answer:

a  >  − 18 or ( − 18 , ∞ )

Step-by-step explanation:

7 0
3 years ago
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