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sergejj [24]
3 years ago
12

What number must be placed in the box in the equation below to produce an equation that has more than one solution: 5u+3(4u-6)=-

3u-27+20u+ ▢
Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
7 0

Answer: the number must be placed in the box is 9

suppose: the number must be placed in the box is x

have:

5u + 3(4u - 6) = -3u -27 + 20u + x

⇔ 5u + 12u - 18 = -3u - 27 + 20u +x

⇔ 17u + 3u - 20u = -27 + 18 + x

⇔ 0 = x - 9

⇔ x = 9

Step-by-step explanation:

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ABCD is a rhombus, where m∠AED = 5x – 10. Use the properties of a rhombus to determine the value of x. Question 10 options: A) x
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Since, diagonals of a rhombus are perpendicular bisector.

\therefore \: m \angle AED = 90 \degree \\  \therefore \: (5x - 10) \degree = 90 \degree \\ \therefore \: 5x - 10 = 90  \\ \therefore \: 5x  = 90 + 10  \\ \therefore \: 5x  = 100  \\ \\  \therefore \: x  = \frac{100}{5}  \\  \\ \huge \red{ \boxed{ \therefore \: x  =20}}

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