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sergejj [24]
3 years ago
12

What number must be placed in the box in the equation below to produce an equation that has more than one solution: 5u+3(4u-6)=-

3u-27+20u+ ▢
Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
7 0

Answer: the number must be placed in the box is 9

suppose: the number must be placed in the box is x

have:

5u + 3(4u - 6) = -3u -27 + 20u + x

⇔ 5u + 12u - 18 = -3u - 27 + 20u +x

⇔ 17u + 3u - 20u = -27 + 18 + x

⇔ 0 = x - 9

⇔ x = 9

Step-by-step explanation:

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3 years ago
D Question 5 5. Given A is between Y and Z and YA = 14x, AZ = 10x and YZ = 12x + 48, find AZ<br>​
Anna007 [38]

Answer:

Step-by-step explanation:

If A is in between Y and Z, then;

YA+AZ = YZ

Given.

YA = 14x,

AZ = 10x and

YZ = 12x + 48

Substitute into the formula

14x+10x = 12x+48

Find x;

24x = 12x+48

24x-12x = 48

12x = 48

x = 48/12

x = 4

Get AZ

AZ = 10x

AZ =10(4)

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3 0
3 years ago
A coin, having probability p of landing heads, is continually flipped until at least one head and one tail have been flipped. (a
Natali [406]

Answer:

(a)

The probability that you stop at the fifth flip would be

                                   p^4 (1-p)  + (1-p)^4 p

(b)

The expected numbers of flips needed would be

\sum\limits_{n=1}^{\infty} n p(1-p)^{n-1}  = 1/p

Therefore, suppose that  p = 0.5, then the expected number of flips needed would be 1/0.5  = 2.

Step-by-step explanation:

(a)

Case 1

Imagine that you throw your coin and you get only heads, then you would stop when you get the first tail. So the probability that you stop at the fifth flip would be

p^4 (1-p)

Case 2

Imagine that you throw your coin and you get only tails, then you would stop when you get the first head. So the probability that you stop at the fifth flip would be

(1-p)^4p

Therefore the probability that you stop at the fifth flip would be

                                    p^4 (1-p)  + (1-p)^4 p

(b)

The expected numbers of flips needed would be

\sum\limits_{n=1}^{\infty} n p(1-p)^{n-1}  = 1/p

Therefore, suppose that  p = 0.5, then the expected number of flips needed would be 1/0.5  = 2.

7 0
3 years ago
Which situation is best described by this number line?
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Answer: B. Ryder had $6.25. He needs to buy school supplies and ends up owing his mother $2.50

Step-by-step explanation: The number line only has single digits and every other answers have extreme changes while B has the lowest change that fits in the number line.

3 0
3 years ago
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Answer:

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Step-by-step explanation:

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