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sveta [45]
3 years ago
5

On vacation, the Jones family drove 320 miles the first day and 400 miles on the second day. If they drove about 60 miles per ho

ur, approximately how many hours did they drive
PLZ HELP MEEEE!!!!!!!!!
Mathematics
1 answer:
Paha777 [63]3 years ago
3 0

Answer:

12 hours spent driving

Step-by-step explanation:

320 + 400 = 720 miles total

720 miles / 60 (1 hour) = 120 hours

Keep in mind: Speed is miles per hour

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On which triangle can the law of cosines be applied once to find an unknown angle measure? Law of cosines: a2 = b2 + c2 – 2bccos
Maksim231197 [3]

Answer:

C) Angle X Y W is 76 degrees. The length of X Y is 5, the length of W Y is 10, and the length of W X is y.

Step-by-step explanation:

On which triangle can the law of cosines be applied once to find an unknown angle measure?

The Law of cosines is given as:

a² = b² + c² - 2bccos(A)

From the options given above, the correct option is Option C

C) Angle X Y W is 76 degrees. The length of X Y is 5, the length of W Y is 10, and the length of W X is y.

This is because:

Law of Cosines helps us to find an unknown side of a triangle when we are given 2 known sides and 1 angle.

In the above question, we are given angle 76 degree, and the length of two sides: The length of X Y is 5, the length of W Y is 10

The unknown side is the length of W X which is represented as y.

Hence, Option C is the correct option.

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3 years ago
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Answer:

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3 years ago
Find the first four terms of this geometric sequence a1 = 5 And r = 6
Elena-2011 [213]
General term of a geometric sequence is 
a(n)=a(1)×r^(n-1)
a1=5
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What is 28 divided by 4?
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1.Encuentra la ecuación de la circunferencia que tiene como ecuación ordinaria (x-4)² + (y+5)²= 25 2- encuentra la ecuación gene
rodikova [14]

Responder:

1) x² + y²-8x + 10y + 16 = 0

2) x² + y² + x + 18y + 33 = 0

Explicación paso a paso:

A partir de la pregunta, debemos expresar la ecuación en la forma estándar de un círculo expresado como;

x² + y² + 2gx + 2fy + c = 0 donde;

(-g, -f) es el centro.

1) Para la ecuación (x-4) ² + (y + 5) ² = 25

Expande el paréntesis;

(x-4) ² + (y + 5) ² = 25

x²-8x + 16 + y² + 10x + 25 = 25

x²-8x + 16 + y² + 10y + 25-25 = 0

Recopile términos similares;

x² + y²-8x + 10y + 16 + 0 = 0

<em>x² + y²-8x + 10y + 16 = 0 </em>

<em>Por lo tanto, la ecuación requerida es x² + y²-8x + 10y + 16 = 0 </em>

<em> </em>

2) Para la expresión (x + 1) ² + (y + 9) ² = 49

x² + x + 1 + y² + 18y + 81 = 49

x² + x + 1 + y² + 18y + 81-49 = 0

Recopile términos similares;

x² + y² + x + 18y + 82-49 = 0

<em>x² + y² + x + 18y + 33 = 0 </em>

<em>Por tanto, la ecuación requerida es x² + y² + x + 18y + 33 = 0</em>

4 0
2 years ago
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