Ask question

Ask question

All categories

olya-2409 [2.1K]

4 years ago

10

A blueprint for a house shows the height of the house to be 3 3/8 inches. The actual house is 21 1/3 feet tall. What is the unit

rate in feet per inch?

1 answer:

Amanda [17]4 years ago

6 0

6.32ft per inch (rounded to the hundredth place).

You can get this number by dividing the total number of feet by the total number of inches

You might be interested in

Evaluate if j = 6: 3] - 10<br><br><br> PLS HELP FAST‼️

OLEGan [10]

Answer:

$\sqrt{25}$

Step-by-step explanation:

5 0

3 years ago

I Need the answer tonight please help

larisa86 [58]

I think D pretty positive because 0 and a negative aren't a natural number

5 0

4 years ago

Read 2 more answers

Solve each system by substitution <br> 5x + 7y = -23<br> Y = -2x - 11

Alenkasestr [34]

Answer:

x = −6

Explanation:

5x + 7y = -23

Y = -2x - 11

Substitute -2x - 11 for y in 5x + 7y = -23

5x + 7(−2x − 11) = −23

Simplify both sides of the equation

5x + 7(−2x − 11) = −23

5x + (7)(−2x ) + (7)(−11) = −23 (Distribute)

5x + −14x + −77 = −23

(5x + −14x) + (−77) = −23 (Combine Like Terms)

−9x + −77 = −23

−9x − 77 = −23

Add 77 to both sides

−9x − 77 + 77 = −23 + 77

−9x = 54

Divide both sides by -9

−9x / -9 = 54 / -9

x = -6

6 0

3 years ago

Pleaze help will give Branliest

Mariulka [41]

Perimeter of the ΔJKL is 48 cm

Solution:

Given $\triangle \mathrm{RST} \sim \Delta \mathrm{JKL}$ .

RS = 8 cm and JK = 12 cm

Perimeter of $\triangle R S T$ = 32 cm

Let us find the perimeter of $\Delta J K L$ .

<u>Property of similarity triangles:</u>

If two triangles are similar, then the ratio of their perimeters is equal to the ratio of their corresponding sides.

$$\frac{\text{Perimeter of}\ \triangle RST }{{\text{Perimeter of}\ \triangle JKL}} =\frac{RS}{JK}$

$$\Rightarrow\frac{32 }{{\text{Perimeter of}\ \triangle JKL}} =\frac{8}{12}$

Do cross multiplication.

$$\Rightarrow 32\times 12 ={8}\times {\text{Perimeter of}\ \triangle JKL}$

$$\Rightarrow 384 ={8}\times {\text{Perimeter of}\ \triangle JKL}$

Divide both sides of the equation by 8.

$$\Rightarrow 48 = {\text{Perimeter of}\ \triangle JKL}$

Hence perimeter of the ΔJKL is 48 cm.

5 0

4 years ago

Brainlyest for best answer

bazaltina [42]

Answer:

21

Step-by-step explanation:

Add all of the numbers together then divide by 5

7 0

3 years ago

Read 2 more answers