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xxMikexx [17]
3 years ago
9

Jeff has a box containing 26 tiles, each with a different letter of the alphabet. he randomly draws 4 letters, one at a time wit

hout replacement. what is the probability that he will choose the letters n, w, b, t?
Mathematics
1 answer:
MArishka [77]3 years ago
8 0
The probability to choose letter n is \frac{1}{26}. After drawing letter n there left 25 letters and the probability to choose the letter w is \frac{1}{25}. After drawing two letters n and w there left 24 letters and then the probability to choose letter b is \frac{1}{24}. After drawing three letters n, w and b there left 23 letters, so the probability to choose letter t is \frac{1}{23}.
Using the product rule for probabilities, you can obtain that P= \frac{1}{26} * \frac{1}{25} * \frac{1}{24}* \frac{1}{23} =0.0000027.
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Answer:

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3 years ago
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Subtract 18 from both sides

32 - 18 = 7t

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14 = 7t

Divide both sides by 7

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4 years ago
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