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xxMikexx [17]
3 years ago
9

Jeff has a box containing 26 tiles, each with a different letter of the alphabet. he randomly draws 4 letters, one at a time wit

hout replacement. what is the probability that he will choose the letters n, w, b, t?
Mathematics
1 answer:
MArishka [77]3 years ago
8 0
The probability to choose letter n is \frac{1}{26}. After drawing letter n there left 25 letters and the probability to choose the letter w is \frac{1}{25}. After drawing two letters n and w there left 24 letters and then the probability to choose letter b is \frac{1}{24}. After drawing three letters n, w and b there left 23 letters, so the probability to choose letter t is \frac{1}{23}.
Using the product rule for probabilities, you can obtain that P= \frac{1}{26} * \frac{1}{25} * \frac{1}{24}* \frac{1}{23} =0.0000027.
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Use the elimination method to solve the system of equations. Choose the
sveticcg [70]

Answer:

C. (2, 1)

Step-by-step explanation:

-3y = x-5

x+ 5y = 7

Subtract x from both sides in the first equation. Write the second equation below it.

-x - 3y = -5

x + 5y = 7

Add the two equations above.

2y = 2

Divide both sides by 2.

y = 1

Substitute y with 1 in the second original equation and solve for x.

x + 5(1) = 7

x + 5 = 7

Subtract 5 from both sides.

x = 2

Answer: C. (2, 1)

6 0
3 years ago
Read 2 more answers
A rectangle is 13 centimeters wide and 18 centimeters long. how long is its diagonal
Naddika [18.5K]
You have to use the Pythagorean theorem a squared plus b squared is c squared so 13 squared plus 18 squared equals c squared. 13x13=169 18x18=324 169+324=493 so c squared is 493 to get c you square root 493 which equals 22.2 so the diagonal, c, is 22.2 centimeters long
7 0
3 years ago
HELP ASAP PLZZZZ
Tcecarenko [31]
QUESTION 1

The given system of equations is

3d - e = 7...eqn(1)
d + e = 5...eqn(2)

To solve by linear combination, we add equation (1) to equation (2) to get,

3d  + d= 7 + 5


4d = 12


We divide through by 4 to obtain,


d =  \frac{12}{4}


d = 3


We put d=3 into equation (2) to get,



3+ e = 5


e = 5 - 3


e = 2


\boxed {The \: solution \: is  \: (3, 2)}



QUESTION 2


The given system is

4x + y = 5 ...eqn(1)

3x + y = 3 ...eqn(2)


To solve by linear combination, we subtract equation (2) from equation (1) to eliminate y from the equation.

This will give us,

4x - 3x = 5 - 3



This implies that,

x = 2


Put x=3 into equation (1) to get,

4(2) + y = 5

8+ y = 5


y = 5 - 8



y =  - 3

The solution is

(2,-3)



QUESTION 3

We want to solve the system;


a – 2b = –2 ....eqn(1)


2a + 2b = 14...eqn(2)

by linear combination.


We need to add equation (1) to equation (2) to eliminate b.


This implies that,

2a + a = 14 +  - 2




Simplify,

3a = 12



Divide both sides by 3 to get,


a = 4
Put a=4 into equation (2) to obtain,



2(4) + 2b = 14


8 + 2b = 14
2b = 14 - 8


2b = 6


b = 3


The ordered pair in the form (a, b) is

(4,3)



QUESTION 4

The given system of equations is


11x + 4y = 18 ...eqn(1)

3x + 4y = 2 ...eqn(2)


We subtract equation (2) from equation (1) to get,


11x - 3x = 18 - 2


8x = 16


x = 2


Put x=2 into equation (2) to obtain,


3(2) + 4y = 2


This implies that,


6 + 4y = 2


4y = 2 - 6


4y =  - 4


y=-1

The correct answer is (2,-1).




QUESTION 5

The given system is ;

2d + e = 8...eqn1

d – e = 4...eqn2


We add the two equations to eliminate e.


This implies that,

2d + d = 8 + 4


3d = 12



We divide both sides by 3 to get,


d = 4


We put d=4 into equation (2) to get,

4 - e = 4

- e = 4 - 4



- e = 0



e = 0


The solution is

(4,0)
7 0
3 years ago
Jada is training for a marathon. She wants to run a total of 25 miles this week. She will run the same distance each day for 6 d
8090 [49]

Answer:

4 1/6

Step-by-step explanation:

4 x 6 = 24

1/6 x 6 = 6/6 = 1

24 + 1 = 25 :)

8 0
3 years ago
Freeeee p0ints!! :) <br> have a good day
Tema [17]

Answer:

thx i ned the points lol

Step-by-step explanation:

bErS

8 0
3 years ago
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