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bija089 [108]
3 years ago
9

Por que una hoja es una textura natural​

Biology
1 answer:
Katyanochek1 [597]3 years ago
8 0

Answer:

Because a leaf is a natural texture is this what your asking.

Explanation:

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Which of the following correctly describes the result of genetic mutations when they occur in a body cell?
PSYCHO15rus [73]

<span>Some mutations don't have any noticeable effect on the phenotype of an organism. This can happen in many situations: perhaps the mutation occurs in a stretch of DNA with no function, or perhaps the mutation occurs in a protein-coding region, but ends up not affecting the amino acid sequence of the protein</span>

<span>
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Measuring Pulse
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Answer:How long each heart beat are apart

Explanation:

the vein isnt conected to ur heart :P

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How is the scientific law different from scientific theory ​
poizon [28]

Scientific law is observations and theory is explanation.

4 0
3 years ago
The answer is 51.0 ml but can someone explain why please
professor190 [17]

Answer:

\boxed{\sf A. \ 51 \ mL}

Explanation:

Amount of water displaced by the sphere will be equal to the volume of complete sphere.

As the sphere completely sinks to the bottom of the cup.

We have been given;

Diameter of sphere (d) = 4.6 cm

So,

\sf Radius \:  of \:  sphere  \: (r) =  \frac{Diameter \:  of \:  sphere \: (d)}{2}  \\  \sf =  \frac{4.6}{2}  \\ \sf  = 2.3 \: cm

Volume of sphere (V):

\boxed{ \bold{V =  \frac{4}{3} \pi {r}^{3} }}

By substituting value of r we get:

\sf \implies V =  \frac{4}{3}  \times \pi \times  {(2.3)}^{3}  \\  \\  \sf \implies V =  \frac{4}{3}  \times 3.14 \times 12.167 \\  \\ \sf \implies V =    \frac{152.81752}{3} \\  \\   \sf \implies V =  50.94 \:  {cm}^{3}  \\  \\   \sf \implies V  \approx 51 \:  {cm}^{ 3}

1 cm³ = 1 mL

\therefore

V = 51 mL

So,

Water displaced by the sphere = 51 mL

6 0
3 years ago
En un cruce entre peces naranjas y peces grises se obtiene una generación (f1) de 50% peces grises . Realice el cruce y explique
Ilya [14]

Answer:

Uno de los progenitores es heterocigoto para color naranja (Nn) y el otro parental es homocigoto recesivo para gris (nn). Al haber una cruza entre un homocigoto recesivo y un heterocigoto, la 50% de la progenie expresa color naranja (Nn), mientras que el otro 50% expresa color gris (nn).

Explanation:

<u>Datos disponibles:</u>

  • Cruce entre peces naranjas y peces grises
  • 50% de la F1 son peces grises
  • Naranja dominante sobre gris

Podemos nombrar el alelo dominante para color naranja <em>N</em>, y al alelo recesivo  para color gris <em>n</em>.

Para que en un cruce entre dos fenotipos distintos, el 50% de la primer camada exprese uno de estos fenotipos, entonces uno de los parentales debe ser heterocigoto, mientras que el otro parental debe ser homocigoto recesivo. De esta forma 50% de la primera generación expresara uno de los fenotipos, mientras que el otro 50% expresará el otro fenotipo.

Supongamos que uno de los parentales lleva el genotipo <em>Nn</em>, y el otro parental es <em>nn</em>.

Cruce:

Parental)      Nn    x     nn

Gametas)   N    n       n    n

Fenotipos) Naranja     Gris

Cuadro de Punnett)      N           n

                            n       Nn         nn

                            n       Nn         nn

F1)  2/4 = 1/2 = 50% de la progenie tendrá genotipo heterocigoto, Nn

     2/4 = 1/2 = 50% de la progenie tendrá genotipo homocigota recesivo,    

     nn

     50% de la progenie será color naranja (Nn)

     50% de la progenie será color gris (nn)

               

3 0
3 years ago
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