For this case we must solve the following equation:
If we apply cubic root to both sides of the equation, then we eliminate the exponent on the left side:
![\sqrt [3] {x ^ 3} = \sqrt [3] {22}\\x = \sqrt [3] {22}](https://tex.z-dn.net/?f=%5Csqrt%20%5B3%5D%20%7Bx%20%5E%203%7D%20%3D%20%5Csqrt%20%5B3%5D%20%7B22%7D%5C%5Cx%20%3D%20%5Csqrt%20%5B3%5D%20%7B22%7D)
That is the exact solution of the equation. Its decimal solution is given by:
![x = \sqrt [3] {22} = 2.8020](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%20%5B3%5D%20%7B22%7D%20%3D%202.8020)
ANswer:
The solution to the equation is
Answer:
(0,0) and (-530,0)
Step-by-step explanation:
If you have to use the quadratic formula, you need to know your A, B, and C values. Your A value is 4, your B is 2120, and your C value, or constant, appears to be zero. Then you need to plug these values into the quadratic formula to get 0 and -530. This would make your roots to be at points (0,0) and (-530,0).
Answer:
a
Step-by-step explanation:
that is the only thing there
Recall that sin²Ф+cos²Ф=1,
so cos²Ф=1-sin²Ф=(1+sinФ)(1-sinФ)
the (1-sinФ) in the numerator cancel with the (1-sinФ) in the denominator, the result is 1+sinФ
A=P(1+r/n)^(nt) where n= number of times compounded yearly, t= time and p= principle
A=723(1+.029/2)^(2*23)
A=$1,401.95 So C
