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3 years ago

11

Inequality to Verbal

1 answer:

faltersainse [42]3 years ago

5 0

Answer:

D. The range is greater than 25 and less than or equal to 31.

Step-by-step explanation:

y is range

≤ = less than or equal to

< = less than

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Today Ian wants to run less than 7/12 mile write a fraction with a denominator of 4 to red present a distance that is less 7/12

bija089 [108]

There are 2 fractions you could write, 2/4, which would be 6/12, or 1/4, which would be 3/12
as you can see both are less than 7/12

6 0

3 years ago

Read 2 more answers

Find the difference,

Airida [17]

Answer:

B 13m+8

Step-by-step explanation:

(20m+3) - (7m-5)

20m+3-7m+5

13m+8

8 0

3 years ago

Read 2 more answers

Hcf of 84 and 49 I'm so lazy

White raven [17]

Answer:

<h2>7</h2>

HCF of 49 and 84 is 7.

Step-by-step explanation:

mark me brainliest

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3 years ago

Finding Hypotenuse Lengths. Find the length of the hypotenuse.

ioda

Answer:

11) $\frac{3\sqrt{5}}{2}$

12) $4\sqrt{5}$

13) $22$

14) $18$

15) $2$

16) $24\sqrt{3}$

Step-by-step explanation:

For these problems I used the pythagorean theorem: $a^{2}+ b^{2}= c^{2}$ and SOHCAHTOA

Sin = $\frac{opposite}{hypotenuse}$

Cos = $\frac{adjacent}{hypotenuse}$

Tan = $\frac{opposite}{hypotenuse}$

11)

First find the length of the bottom side by using Cos

$cos(60)=\frac{x}{3}$

$3(cos(60))=x$

$1.5=x$

Then plug it into the formula for the pythagorean theorem to find the hypotenuse

$3^{2}+ 1.5^{2}= c^{2}$

$9+2.25=c^{2}$

$\sqrt{11.25}=\sqrt{c^{2}}$

$\frac{3\sqrt{5}}{2}$

12)

Find the length of the bottom side using Cos

$cos(60)=\frac{x}{8}$

$8(cos(60))=x$

$4=x$

Then plug it into the formula for the pythagorean theorem to find the hypotenuse

$8^{2}+ 4^{2}= c^{2}$

$64+16=c^{2}$

$\sqrt{80} =\sqrt{c^{2} }$

$4\sqrt{5}$

13)

Find the length of the other side by using Tan

$tan(30)=\frac{x}{11\sqrt{3} }$

$11\sqrt{3}* (tan(30)=x$

$11=x$

Then plug it into the formula for the pythagorean theorem to find the hypotenuse

$(11\sqrt{3}) ^{2}+ 11^{2}= c^{2}$

$363+121=c^{2}$

$\sqrt{484} =\sqrt{c^{2}}$

$22$

14)

(This is probably an easier way to do these problems)

Find the hypotenuse by using Cos ( $\frac{adjacent}{hypotenuse}$ )

$cos(60)=\frac{9}{x}$

$cos(60)x=9$

$x=\frac{9}{cos(60)}$

$x=18$

15)

Find the hypotenuse using Sin ( $\frac{opposite}{hypotenuse}$ )

$sin(30)=\frac{1}{x}$

$sin(30)x=1\\x=\frac{1}{sin(x)}$

$x=2$

16)

Find the hypotenuse using Cos ( $\frac{adjacent}{hypotenuse}$ )

$cos(60)=\frac{12\sqrt{3} }{x}$

$cos(60)x=12\sqrt{3}$

$x=\frac{12\sqrt{3} }{cos(60)}$

$x=24\sqrt{3}$

5 0

4 years ago

If an airplane travels 250 miles per hour, how far will it travel in 8 hours?

Slav-nsk [51]

Answer:

2000 ;)

Step-by-step explanation:

250mph x8 hours =2000

4 0

3 years ago