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soldi70 [24.7K]
3 years ago
13

HELPPPPPPPPPP!!!!!!!!!!

Mathematics
1 answer:
juin [17]3 years ago
4 0

Answer:

The last one

Step-by-step explanation:

measure angle 2 and 6 to see if congruent

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PLEASE HELP ME!
Firdavs [7]

Answer:

a

Step-by-step explanation:

educational guess ;)

8 0
3 years ago
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The length of a rectangle is four more than its width. If the area of the rectangle is 12, find the length of the rectangle.
Kobotan [32]

Answer:

I don’t know but I have the same question with different numbers

Step-by-step explanation:

8 0
3 years ago
Please help me find the total area of the composite figure below (geometry)
Akimi4 [234]

Answer:

lw + \frac{1}{2} × π × (\frac{l}{2} )^{2} ⇒ Answer D is correct

Step-by-step explanation:

First, let us find the area of the semi-circle.

Area = \frac{1}{2} × π × r²

<u>Given that,</u>

diameter of the semi-circle is ⇒ <em>l</em>

∴ radius ⇒ <em>l / 2</em>

<u>Let us find it now.</u>

Area = \frac{1}{2} × π × r²

Area =  \frac{1}{2} × π × (\frac{l}{2} )^{2}

<u>                                                     </u>

Secondly, let us find the area of the rectangle.

Area = length × width

<u>Given that,</u>

length ⇒ <em>l</em>

width ⇒ w

<u>Let us find it now.</u>

Area = length × width

Area = l ×w

Area = lw

<u>                                                      </u>

And now let us <u>find the total area.</u>

Total area =  Area of the rectangle + Area of the semi - circle

Tota area = lw + \frac{1}{2} × π × (\frac{l}{2} )^{2}

8 0
2 years ago
HELP. WILL MARK BRAINLIEST. WHAT IS THE CORRECT ANSWER?
kari74 [83]

7/8 * cm/ month * 5 months =

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4 3/8 cm

Answer: 4  3/8 cm

6 0
3 years ago
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a radioactive substance has a half-life of 2 seconds. A scientist begins with a sample of 20 grams. How much of the substance re
s344n2d4d5 [400]

Answer:

1.25 g

Step-by-step explanation:

you start with 20g at 0 seconds.

divide by half after 2 seconds and you have 10g.

at 4 seconds you have 5g.

at 6 seconds you have 2.5g.

at 8 seconds you have 1.25g.

5 0
2 years ago
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