Answer:

Step-by-step explanation:
Given


Required
Find PQR
Since both angles are supplementary, we have:

This gives:


Collect Like Terms


Divide through by 10

Substitute 20 for X in 


Answer:
C
Step-by-step explanation:
pls mark brainliest
multiply the numerator and denominator by the same number so, that all the fractions have a denominator of 12.
I think it’s 2x1 hope this helps
Add both equations giving x=1
Sub back into any equation which gives you y=1
Answer:
Which of the following is a common sign that a chemical change has occurred?
Step-by-step explanation:
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