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ANTONII [103]
2 years ago
10

Fine the area if the figure.(Sides meet at the right angles)

Mathematics
1 answer:
Liula [17]2 years ago
6 0

Answer:

45 cm²

Step-by-step explanation:

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4 0
3 years ago
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Carol successfully increases her business to 200 customers per day. However, her total cost for doing so is 50% greater than the
kramer

Carol's Steakhouse, the total cost of serving 150 customers per day is $900. Carol is interested in increasing her business, but is concerned about the effect on marginal cost.

Carol successfully increases her business to 200 customers per day. However, her total cost for doing so is 50% greater than the expected $1,600. What percent greater is the actual marginal cost than the expected marginal cost, to the nearest full perc

Answer:

214

Step-by-step explanation:

We have been given

C1 = $900

Q1 = 259

Then c2 = $1600

Q2 = 200

M = 1600-900/50

= 14

For real,

C1 = 900

C2 = 2400

Q1 = 150

Q2 = 50

1500/50 = 30

30/14 x 100

= 214

It is greater by 214 percent

5 0
3 years ago
A bag contains eight blue marbles six Green marbles 12 yellow marbles and 10 orange marbles a marble is drawn at random from the
Marta_Voda [28]
28/36=7/9
explanation












hope that helped
3 0
3 years ago
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Toben bought ​ 5 1/2 ​ pounds of chicken, which cost $3.50 per pound. What was the total cost of the chicken?
schepotkina [342]

The chicken cost $1.57 per pound.

You figure this out by dividing the total amount of chicken 5.5lbs (5 1/2) by the cost per pound.

5.5 / 3.50 = 1.57

4 0
4 years ago
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A company services home air conditioners. It is known that times for service calls follow a normal distribution with a mean of 7
SCORPION-xisa [38]

Answer:

The probability that exactly eight of them take more than 93.6 minutes is 5.6015 \times 10^{-6} .

Step-by-step explanation:

We are given that it is known that times for service calls follow a normal distribution with a mean of 75 minutes and a standard deviation of 15 minutes.

A random sample of twelve service calls is taken.

So, firstly we will find the probability that service calls take more than 93.6 minutes.

Let X = <u><em>times for service calls.</em></u>

So, X ~ Normal(\mu=75,\sigma^{2} =15^{2})

The z-score probability distribution for the normal distribution is given by;

                              Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = mean time = 75 minutes

           \sigma = standard deviation = 15 minutes

Now, the probability that service calls take more than 93.6 minutes is given by = P(X > 93.6 minutes)

       P(X > 93.6 min) = P( \frac{X-\mu}{\sigma} > \frac{93.6-75}{15} ) = P(Z > 1.24) = 1 - P(Z \leq 1.24)

                                                                = 1 - 0.8925 = <u>0.1075</u>

The above probability is calculated by looking at the value of x = 1.24 in the z table which has an area of 0.8925.

Now, we will use the binomial distribution to find the probability that exactly eight of them take more than 93.6 minutes, that is;

P(Y = y) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; y = 0,1,2,3,.........

where, n = number of trials (samples) taken = 12 service calls

            r = number of success = exactly 8

            p = probability of success which in our question is probability that

                   it takes more than 93.6 minutes, i.e. p = 0.1075.

Let Y = <u><em>Number of service calls which takes more than 93.6 minutes</em></u>

So, Y ~ Binom(n = 12, p = 0.1075)

Now, the probability that exactly eight of them take more than 93.6 minutes is given by = P(Y = 8)

               P(Y = 8)  =  \binom{12}{8}\times 0.1075^{8} \times (1-0.1075)^{12-8}

                             =  495 \times 0.1075^{8} \times 0.8925^{4}

                             =  5.6015 \times 10^{-6} .

6 0
3 years ago
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