Answer:
The total number of ways in which three winners can come in is 990 ways.
Step-by-step explanation:
It is provides that the number of automobiles entering the race is: <em>n</em> = 11.
It is also provided that there were no ties.
There are supposed to be three winners for the race.
- The number of ways the first winner can come in is: 11 ways.
- The number of ways the second winner can come in is: 10 ways.
- The number of ways the third winner can come in is: 9 ways.
Compute the total number of ways in which three winners can come in as follows:
Number of ways in which the first three finishers come in is

Thus, the total number of ways in which three winners can come in is 990 ways.
f(-2) = 2, this is because where x = -2, y = 2
Step-by-step explanation:
Hello there!
Calulate the area of each side:
(Top and bottom)
18x11x2=396
3x11x2=66
3x18x2=108
All together=570 in ^2
A. X is the number of years after 2000
2006-200 = 6 years.
Replace x with 6 and solve:
105(6)^2 + 680(6) + 4296 = 12,156
Answer for part a: 12,156
Answer for part B.
There was just over 12,000 in 6 years , to get to 21,500 would be a little over 9,000 more 9/12 = 0.75
6 years x .75 = 4.5 years
6 + 4.5 = 10.5 years round to 10 years for estimating purposes
Answer for part b: about 10 years