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Svetach [21]
3 years ago
5

I need helppppppppppppp

Mathematics
1 answer:
ohaa [14]3 years ago
5 0
Simplify

4ax+12-3ax=25+3a

ax+12=25+3a

ax-3a=25-12

a(x-3)=13
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When 50 mL of water is added, the graduated cylinder has a mass of 180 g. If a rook is added to the graduated cylinder, the wate
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Answer:

2.25 (or \frac{9}{4}) g/mL

<u>Skills needed: Density</u>

Step-by-step explanation:

1) Briefly, let's cover what density is:

- It is \frac{mass}{volume}

- Measures the mass per unit of volume

- In this situation the formula for density is: \frac{m_f-m_i}{v_f-v_i}

---> m_f is the final mass

---> m_i is the initial mass

---> v_f is the final volume

---> v_i is the initial volume

2) In this case, we start out with a mass of 180 grams as stated in the problem, and also 50 mL of water initially.

This means that:

- m_i is 180 g

- v_i is 50 mL

3) Also, we end up with 270 g in mass, and 90 mL of water finally.

- m_f is 270g

- v_f is 90 mL

4) We can find density by substitute given the values above:

\frac{270-180}{90-50} = \frac{90}{40} = \frac{9}{4} \text{ or } 2.25

5) Our answer is 2.25 g/mL (since mass is grams (g), and volume is milliliters (mL) in the problem above).

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